Linear function and is it linear?

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The discussion centers on determining the linearity of a function f defined by the points f(0,0)=0, f(2,0)=3, and f(5,0)=6. The user successfully derived the equation of a linear function z=2x-y+2, which intersects the xy-plane along the line y=2x+2 and contains the point (1,2,2). To ascertain if function f is linear, it is essential to check if the vectors formed by the points are parallel, indicating that they lie on a straight line.

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I had to find an equation of a linear function z=c+mx+ny whose graph intersects the xy plane in the line y=2x+2 and contains the point (1,2,2)

I got the answer as z=2x-y+2

Now I have to see if the function f which satisfies f(0,0)=0, f(2,0)=3 and f(5,0)=6 linear? and explain it.

I have no clue what to do now. Can anyone help me? Thanks!
 
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You need to find the vectors between the three points given and take the cross product of them. Use this resulting vector and one of the given points, you can determine the equation of a plane. If this equation satisfies all three given points, the function f is linear.
You may want to refer to http://en.wikipedia.org/wiki/Linear for the necessary explanation.
 
multicalcprob said:
I had to find an equation of a linear function z=c+mx+ny whose graph intersects the xy plane in the line y=2x+2 and contains the point (1,2,2)

I got the answer as z=2x-y+2
Yes, that is correct.

Now I have to see if the function f which satisfies f(0,0)=0, f(2,0)=3 and f(5,0)=6 linear? and explain it.

do (0,0,0), (2,0,3) and (5,0,6) lie on a straight line? If so the vectors form (0,0,0) to (2,0,3) and from (0,0,0) to (5,0,6) must be parallel. That means one vector must be a multiple of the other.
 

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