Linear Interpolation for Given Function

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SUMMARY

The discussion centers on determining the linear interpolant for the function defined by specific values at points: f(-π)=4, f(-π/2)=5/4, f(0)=1, f(π/2)=-3/4, and f(π)=0. The correct approach involves using linear interpolation formulas, specifically the equation of the straight line connecting points (-π, 4) and (-π/2, 5/4). The first interpolant for the interval from -π to -π/2 is given as 4 - 11(x + π)/(2π). The user expresses confusion regarding the problem's requirements, questioning whether they need to provide all interpolants or just the connecting equations.

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ForTheGreater
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Decide the linear interpolant

f(-pi)=4 f(-pi/2)=5/4 f(0)=1 f(pi/2)=-3/4 f(pi)=0

the function is (1/pi2 ) (x-pi)2 - cos2 (x-pi/2)

Don't know how to do this. I tried lagrange basis functions f(x0)(x1-x)/(x1-x0)+f(x1)(x-x0)/(x1-x0)

But it doesn't turn out right.

The answer for the first interpolant (interval -pi to -pi/2) is: 4-11(x+pi)/(2pi)
 
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I sense a contradiction between the problem statement "Decide the interpolant" and the book answer "The answer for the first interpolant ... is...".
Could it be that all you are asked to provide is the four equations "connecting the dots" ?

(The book answer for the first section is the equation of the straight line through ##(-\pi, 4)## and ##(-\pi/2, 5/4)##. )

--
 
I have the answer here, it wasn't in the problem.

I'm suppose to give the interpolant in all intervals, or as you put it connect the dots.

Thank you!
 

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