Linear Speed of Earth at latitude 40° N

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Homework Help Overview

The discussion revolves around calculating the linear speed of a point on Earth's surface at latitude 40° N, following the determination of angular speed. The original poster has successfully calculated the angular speed but seeks clarification on the derivation of the radius at that latitude, specifically questioning the use of the cosine function in the formula.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand why the radius at latitude 40° N is expressed as Rcos(40°) and questions the underlying reasoning for using the cosine function. They also ponder whether a different approach would be needed for other latitudes or longitudes.

Discussion Status

Participants are actively engaging with the concepts involved, with one providing a detailed explanation of the geometry related to circles of latitude. The original poster expresses appreciation for the clarification, indicating that the discussion is productive and informative.

Contextual Notes

The original poster is navigating the complexities of spherical geometry and the implications of latitude on calculations, indicating a need for visual aids to enhance understanding.

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Homework Statement


a) What is the angular speed ω about the polar axis of a point on Earth's surface at latitude 40° N? (Earth rotates about that axis.) I solved this part

b) What is the linear speed v of the point?

Homework Equations



v = ωr where r = radius of Earth at latitude 40°N

The Attempt at a Solution



I found out that r = Rcos(40°) (where R = radius of Earth) but I'm failing to understand why. How am I supposed to know to use cos(40°)? Is it a component of some sort? Where does it come from?

If the problem said longitude 40° E or W, would I then use sin(40°)? Also would I have to know to put a negative sign depending on N, S, E, W?
 
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Think about a circle of latitude. It is also known as a parallel. The circle of latitude 0, the equator, has the radius equal to that of the Earth. As the latitudes go up (Northbound or Southbound), their circles become smaller, eventually becoming just points at the poles.

Now, the question is, what is the radius of the parallel at a latitude between the equator and the pole? The truth is, it is complicated. But frequently we can assume the Earth is a perfect sphere.

Refer to the attached diagram. It depicts the intersection of the spherical Earth with a plane perpendicular to the plane of the equator. NS is the polar axis. The equator is represented by EW, the circle of latitude is by E'W'. Obviously, CE = CW = the radius of the Earth. C'E' = C'W' = the radius of the circle of latitude.
 

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Wow, great explanation! Thanks so much. I wanted to ask if someone could draw a picture describing what's going on but thought that might be too much. Yet, you did it on your own.
 
Well, there was a certain Mr. Lagrange, who wrote a book - a very important book! - on mechanics without a single drawing. It was very hard to read. His students did not understand him, either, perhaps because he had the same trait while lecturing. That shows that no amount of mathematical talent and eloquence can't substitute a good drawing. When I realized just how lengthy and bizarre a text-only explanation would be, spending a few minutes on drawing seemed like a major win :)
 

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