Linear Transformation: Solving Coefficient Matrix and Evaluating T(e1) and T(e2)

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SUMMARY

The discussion focuses on solving a linear transformation problem involving a coefficient matrix and evaluating transformations T(e1) and T(e2). The coefficient matrix A is confirmed as:

A =
1 -2
3 1
0 2

For the transformations, T(e1) is calculated as T[1 0]^t = [1 3 0]^t and T(e2) as T[0 1]^t = (-2 1 2)^t. The calculations are validated by other participants in the discussion.

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Clandry
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I attached the problem. I'm not sure if I'm misinterpreting the question, but this problem seems really easy, which is usually not the case with my class.

for part a) isn't that just the coefficient matrix of the right hand side?
This makes A:
1 -2
3 1
0 2



for part b) T(e1)=T[1 0]^t=[1 3 0]^t
T(e2)=T[0 1]^t=(-2 1 2)^t
Is this right?
 

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Clandry said:
I attached the problem. I'm not sure if I'm misinterpreting the question, but this problem seems really easy, which is usually not the case with my class.

for part a) isn't that just the coefficient matrix of the right hand side?
This makes A:
1 -2
3 1
0 2



for part b) T(e1)=T[1 0]^t=[1 3 0]^t
T(e2)=T[0 1]^t=(-2 1 2)^t
Is this right?

Looks good to me.
 

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