nehap.2491
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suppose that vectors in R3 are denoted by 1*3 matrices, and define T:R4 to R3 by T9x,y,z,t)=(x-y+z+t,2x-2y+3z+4t,3x-3y+4z+5t).Find basis of kernel and range.
The discussion revolves around finding the basis of the kernel and range of a linear transformation defined from R4 to R3. Participants explore methods for calculating the kernel and image of the transformation, as well as discussing the implications of dimensionality in this context.
Participants express differing methods for calculating the image of the transformation, with some advocating for a direct approach using basis vectors while others suggest solving systems of equations. There is no consensus on the preferred method, and the discussion remains unresolved.
Some participants' approaches depend on the linear independence of the set of transformed basis vectors, which may not be established without further analysis. Additionally, the dimensionality relationship mentioned may require clarification regarding the specific transformation in question.
Thank you!micromass said:Ow, for the image you won't need to do all that stuff, I'm sorry.
You'll first have to find a basis of R4, call this {e1,e2,e3,e4}. Then {T(e1),T(e2),T(e3),T(e4)} is a set which spans the image. If this set is linear independent, then it's a basis. If not, then remove some vectors until it is linear independent...
Thank you!Outlined said:If you are open to it, the equation below (in case f : V -> W) might even help:
dim(ker(f)) + dim(Im(f)) = dim(V)