Linearity in Differential Equations

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The differential equation yy' + 2 = 0 is not linear due to the presence of the product of the dependent variable y and its derivative y'. The definition of linearity requires that the coefficients a_0(t), a_1(t), etc., be functions of the independent variable t only, not involving the dependent variable y. The attempt to redefine y as a function of t does not satisfy the criteria for linearity. Therefore, the conclusion is that the equation is non-linear. Understanding the distinction between linear and non-linear differential equations is crucial for solving them correctly.
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Homework Statement



Is the following differential equation linear:

yy' + 2 = 0

The Attempt at a Solution



I have the definition of linear as being a_0 (t) y^{(n)} + a_1(t) y^{n-1} + a_2 (t) y^{n-2} ... = 0. Now, presumably y is a function of t. Thus, I could define y = a_0 (t) and let n=1. Thus I would satisfy my definition of linearity in differential equations. Thus, the differential equation is linear.

Is it not so?
 
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No, a_0(t) has to be a known function of t, not y or anything involving y. This equation is non-linear because you have a product of things "involving" the dependent variable y.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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