Liquid Problem with Bernoulli's Equation

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sophzilla
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A water pipe having a 2.6 cm inside diameter carries water into the basement of a house at a speed of 0.90 m/s and a pressure of 240 kPa. If the pipe tapers to 1.6 cm and rises to the second floor 7.5 m above the input point, what are the (a) speed and (b) water pressure at the second floor?

I tried to set it up as:

Handwritten-style equation setup for Bernoulli's equation: P0 + ½ρv1² + ρgH = P0 + ½ρv2² + ρgh, with values P0 = 240,000 Pa, ρ = 1000 kg/m³, v1 = 0.9 m/s, H = initial height taken to be zero, v2 unknown, h = 7.5 m.


But clearly it's wrong because I didn't take into consideration the area (given the diameter) etc.

I would appreciate any help. Thank you.
 
Oh, but to solve this problem you'll need to use your last topic equation (the continuity equation :wink: )
 
All righty...

if it's A1V1 = A2V2...do we take into consideration the final height?