How Do You Calculate Head Loss in a Venturi Meter Using Bernoulli's Equation?

[foo9008]

Homework Statement

A venturi meter is being calibrated horizontally and has a diameter of 75mm at the entrance and 50mm at the throat . The flow rate is obtained by measuring the time required to collect certain amount of water . The average number of measurement gives 0.614m^3 of water in 55.82 second . If the pressure gauge at the inlet reads 20kN/ (m^2) more than the throat , calculate the head loss due to friction using Bernoulli's equation

Homework Equations

The Attempt at a Solution

for the first step , i have use the special formula(refer to the second and third attachment) to find the therorical velocity at point 2 ( assume no energy loss) , so , i got V2 = 7.07m/s[/B]

then i found the real flow rate = 0.011(m^3) / s

assuming no loss at point 1 , i equate A2V2 = A1V1
so , i got V1= 3.14m/s
then substitute all the values that i found into the Bernoulli's equation , i found the head loss . Is my working correct ? I don't have the answer with me.

 

[foo9008]

is the actual flow rate = 0.614/55.82 = 0.011(m^3) / s ?

 

[foo9008]

anyone can try to reply ?

 

[foo9008]

bump