LLT-Factorization: Lower Triangular Matrix with Positive Diagonal for 4x3 Matrix

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The discussion focuses on finding the LLT-factorization of a given 4x3 matrix, where L is a lower triangular matrix with positive diagonal elements. To solve the problem, one must express the entries of LLT in terms of the entries of L and equate them with the corresponding entries of the provided matrix. This process involves setting up equations based on the matrix structure, similar to a simpler example with a 1x1 matrix. The solution will yield multiple equations to solve, reflecting the dimensions of the matrix. The key takeaway is that the positive diagonal condition of L is crucial in determining the final values.
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Homework Statement


Determine directly the LLT-Factorization, in which L is a lower triangular matrix with positive diagonal elements, for the matrix

| 4 1/2 1 |
| 1/2 17/16 1/4 |
| 1 1/4 33/64|

Homework Equations


I don't know.

The Attempt at a Solution


I don't know what to do; please help!

Thanks!
 
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You mean LLT, where LT is the transpose of L? This is easy, why don't you just do it? Let L be an arbitrary lower triangular matrix, and compute the entries of LLT in terms of the entries of L. Then equate them with the corresponding entries in the matrix you're given to work with, and solve the equations. For example, if you had a 1x1 matrix (7), and were asked to find the LLT factorization, you let L = (a) be an arbitrary lower triangular matrix. Then you can compute the entries of LLT in terms of the entries of L: LLT = (a)(a) = (a2). Then you equate entries of this matrix with the entries of the matrix you're working with, (7). So you get a2 = 7. So a is either the postive or negative square root of 7, but since we have the condition "L has positive elements on its diagonal" we know a to be the positive root of 7. Your problem is similar, it's just that you'll get 3 + 2 + 1 = 6 equations instead of just 1 equation.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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