Proving Lower Triangular Matrices When i > j

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Homework Help Overview

The discussion revolves around proving that if matrix A is lower triangular and the ith row and jth column are deleted, the resulting matrix B_ij is also lower triangular when i > j. Participants are exploring the properties of lower triangular matrices and the implications of deleting specific rows and columns.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to prove the statement by contradiction and questions whether their understanding of lower triangular matrices is correct. They explore examples with a 4x4 matrix to illustrate their reasoning.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on visualizing the matrix transformations. There is a recognition of the need to clarify definitions and assumptions regarding lower triangular matrices, particularly in relation to the deletion of rows and columns.

Contextual Notes

Participants note potential confusion regarding the definition of lower triangular matrices and the outcomes of specific deletions, indicating a need for further exploration of these concepts.

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Homework Statement


Prove that is ##A## is lower triangular and ##B_{ij}## is the matrix that results when the ith row and jth column of A are deleted, then ##B_{ij}## is lower triangular if i > j.

Homework Equations

The Attempt at a Solution



I know that a square matrix is lower triangular if and only if the jth column starts with at least j-1 zero's for every j.

I am attemting to prove this by contradiction.
If i = j, then the jth column of B has j-1 zeros, but this is true?
if i was to take a 4 x 4 lower triangluar matrix and delete its first row and first column would the 1st,2nd,3rd,4th columns have 0,1,2,3 zeros respecively?Lets ignore that, prehaps I am saying/doing something silly, to finish my proof by contradiction i also have to show that for i < j, we don't have a lower triangular matrix.

if the ith row and the (i+n)th collumn, where n is a postitive integer, of A is deleted, then the ...

ah I am really not getting this one guys. I am lost.
 
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Have i not followed the forums rules? if not could someone please point out the error of my ways
 
HMPARTICLE said:
Have i not followed the forums rules? if not could someone please point out the error of my ways

I think you have not done "enough" work on your own to satisfy PF requirements. You ask: "if i was to take a 4 x 4 lower triangluar matrix and delete its first row and first column would the 1st,2nd,3rd,4th columns have 0,1,2,3 zeros respecively?" I do not see why you cannot answer this for yourself: just draw a sketch of what a 4 x 4 lower triangular matrix must look like, then remove its first row and column. What does it look like now? Try to generalize this to removing row ##r## and column ##c## from a lower-triangular matrix, where ##r = c##. What does the new matrix look like? Ditto if ##r > c##.
 
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Thanks, Ray. Maybe i should have made what i HAD done already a little more clear.

I have already done what you said, regarding a 4x4 matrix and eliminating the first row and column, what results is another lower triangular matrix. the question asks me to show that that if i > j then ##B_{ij}## is a lower triangluar matrix. but in the 4 x 4 example, when i = j, ##B_{ij}## is a lower triangular still, so is proof by contradtiction not the way to go?

in summary;
I have found by experiment, when i = j, ##B_{ij}## is still lower triangular
Also using a 4 x4 matrix as an experiment, when the first row and second column are deleted, what results is another lower triangular matrix. that is i < j

finally, when the second row and the first column are deleted, that is i > j, now, this is not lower triangular, since the first row is a row of zeros.

Prehaps I am not understanding the question, but what is evedent from experiment is that the opposite of what i have to prove is true.
I hope my definition of a lower triangular is correct;
that is, each entry to the right of the main diagonal is zero.

That is where my confusion lies.
 
Last edited:
HMPARTICLE said:
Thanks, Ray. Maybe i should have made what i HAD done already a little more clear.

I have already done what you said, regarding a 4x4 matrix and eliminating the first row and column, what results is another lower triangular matrix. the question asks me to show that that if i > j then ##B_{ij}## is a lower triangluar matrix. but in the 4 x 4 example, when i = j, ##B_{ij}## is a lower triangular still, so is proof by contradtiction not the way to go?

in summary;
I have found by experiment, when i = j, ##B_{ij}## is still lower triangular
Also using a 4 x4 matrix as an experiment, when the first row and second column are deleted, what results is another lower triangular matrix. that is i < j

finally, when the second row and the first column are deleted, that is i > j, now, this is not lower triangular, since the first row is a row of zeros.

Prehaps I am not understanding the question, but what is evedent from experiment is that the opposite of what i have to prove is true.
I hope my definition of a lower triangular is correct;
that is, each entry to the right of the main diagonal is zero.

That is where my confusion lies.

When you omit row 2 and column 1 you get a matrix that is again lower triangular. The fact that the first row is all zero is irrelevent; all that matters is that elements strictly to the right of the diagonal are zero---and they are in your case.
 

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