Lob vs. Bullet Pass: Initial Speed and Launch Angle Calculation

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The discussion focuses on calculating the launch angle of a lob pass thrown at an initial speed of 21.5 m/s with a flight time of 2.97 seconds. It also addresses finding the initial speed and time of flight for a bullet pass launched at a 25-degree angle. Participants emphasize the use of kinematic equations of motion to solve these problems. The conversation highlights the importance of understanding these equations for accurate calculations. Overall, the thread aims to clarify the application of physics principles in sports-related scenarios.
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the lob pass is thrown with an initial speed of 21.5 m/s and its time of flight is 2.97s. What is its launch angle?

The bullet pass is thrown with a launch angle of 25 degrees. What is the initial speed of this pass? What is the time of fight of the bullet pass?

what formulas and how is this worked out?
 
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perplexed1205 said:
the lob pass is thrown with an initial speed of 21.5 m/s and its time of flight is 2.97s. What is its launch angle?

The bullet pass is thrown with a launch angle of 25 degrees. What is the initial speed of this pass? What is the time of fight of the bullet pass?

what formulas and how is this worked out?

Welcome to the PF. You use the kinematic equations of motion, which you no doubt are studying now. What are those equations? How would you use them to start to solve these problems?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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