(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 1.5 cm tall object is placed 0.50 m to the left of a diverging lens with a focal length of 0.20 m. A converging lens with a focal length of 0.17 m is located 0.08 m to the right of the diverging lens.

a)What is the location of the final image with respect to the object? answer = final image is lcoated 1.3 m to the right of the object

b)What is the height and orientation with respect to the orginal object of the final image?

answer = 1.4 cm, inverted

2. Relevant equations

1/q+1/p =1/f

M=hi/h =-q/p

3. The attempt at a solution

Ok, well i need to figure out part a before I can do part b...so

I did 1/p1+1/q2=1/f

1/0.5+1/q=-1/0.2 (negative focal length for diverging)

solve for q = -0.14285

I'm a little confused, when I draw my picture to help me visualize where the image is...i dont know whether or not to add the 0.08 or subtract it ...

I thought I would add it (negative q means the image is in front of the lens (virtual))

so i did...

1/0.22285 +1/q2=1/0.17

1/q2 = 1.39 but if i inverse it then it become 0.71 and that is not the answer....hm

I can't seem to figure this out, please help!!! thanks in advance!

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# Homework Help: Location final image diveraging and converging lens

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