1. The problem statement, all variables and given/known data A 1.5 cm tall object is placed 0.50 m to the left of a diverging lens with a focal length of 0.20 m. A converging lens with a focal length of 0.17 m is located 0.08 m to the right of the diverging lens. a)What is the location of the final image with respect to the object? answer = final image is lcoated 1.3 m to the right of the object b)What is the height and orientation with respect to the orginal object of the final image? answer = 1.4 cm, inverted 2. Relevant equations 1/q+1/p =1/f M=hi/h =-q/p 3. The attempt at a solution Ok, well i need to figure out part a before I can do part b...so I did 1/p1+1/q2=1/f 1/0.5+1/q=-1/0.2 (negative focal length for diverging) solve for q = -0.14285 I'm a little confused, when I draw my picture to help me visualize where the image is...i dont know whether or not to add the 0.08 or subtract it ... I thought I would add it (negative q means the image is in front of the lens (virtual)) so i did... 1/0.22285 +1/q2=1/0.17 1/q2 = 1.39 but if i inverse it then it become 0.71 and that is not the answer....hm I can't seem to figure this out, please help!!! thanks in advance!