Logarithm of a Complex number question?

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SUMMARY

The discussion focuses on calculating the logarithm of a complex number, specifically ln(-3 - 3√2 i). The user correctly identifies the modulus and argument of the complex number, resulting in ln(√27) + i(-3π/4 + 2πk). Additionally, they explore the logarithm of a negative real number, ln(-c), leading to ln(c) + i(π + 2πk). The principal value is established for k = 0, but the user seeks clarification on the next steps, particularly regarding the angle calculation.

PREREQUISITES
  • Complex number theory
  • Logarithmic functions of complex numbers
  • Understanding of modulus and argument
  • Trigonometric functions, specifically arccosine
NEXT STEPS
  • Review the properties of complex logarithms
  • Practice calculating the argument of complex numbers
  • Explore the implications of different values of k in complex logarithms
  • Learn about the principal branch of the logarithm function
USEFUL FOR

Students studying complex analysis, mathematicians working with logarithmic functions, and anyone seeking to deepen their understanding of complex number operations.

Mandynash
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Homework Statement



The question is located here http://i51.tinypic.com/2cge9mt.jpg


Homework Equations



My a value is -3
my b value is -3sqrt(2)
my c value is -2.4

The Attempt at a Solution



1) ln(-3 - 3 sqrt(2) i)
= Ln |-3 - 3 sqrt(2) i| + i arg(-3 - 3 sqrt(2) i)
= ln sqrt(27) + i (-3π/4 + 2πk), for any integer k

2) ln(-c) = Ln |-c| + arg(-c) = ln c + i(π + 2πk) for any integer k.

(Principal value occurs for k = 0.)


Managed to get this far but I have no idea what I need to do next! Thanks in advance for the help.
 
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For 2) you just have to plug c=2.4.

For 1) you may want to check the angle again. I get \arccos\left(-\frac{\sqrt{3}}{3}\right)
 

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