aorick21
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Prove x <=> y is logically equivalent to (x-->y) ^ ((~x)-->(~y)).
The discussion revolves around proving the logical equivalence between the expression x <=> y and the expression (x-->y) ^ ((~x)-->(~y)). This involves concepts from propositional logic.
The discussion is active, with participants offering different approaches and questioning the requirements for the proof. Some guidance has been provided regarding the use of truth tables and rewriting expressions, but no consensus has been reached on a specific method.
There is an indication that participants may have varying levels of familiarity with the concepts involved, as evidenced by the comments about the necessity of understanding truth tables and the nature of the proof required.
aorick21 said:Prove x <=> y is logically equivalent to (x-->y) ^ ((~x)-->(~y)).
TimNguyen said:I'd just use a truth table.
If you don't know what that is, then I don't think you belong in math.