Longitudinal strain rate derivation

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SUMMARY

The discussion focuses on the derivation of longitudinal strain rate in fluids, specifically the relationship between the strain rate dφ/dt and the velocity field derivative du/dx. The user expresses confusion regarding the absence of intermediate steps in the derivation and the origin of the 0.5 factor in the equation. The discussion references a resource from the University of Edinburgh's fluid mechanics course, which may provide additional context for understanding the trigonometric identities involved in this derivation.

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  • Understanding of fluid mechanics principles
  • Familiarity with strain rate concepts
  • Knowledge of trigonometric identities
  • Basic calculus, specifically derivatives
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Hi,

The attachment below is about strain rate in fluids*. It shows how the strain rate d\phi/dt is related to the velocity field derivative du/dx when you stretch the element in x (i.e. longitudinal strain).

It has no intermediate steps, and I can't see how the angle has been related to the velocity field (or where the 0.5 factor comes from).

Thanks very much.

*From website: http://www.see.ed.ac.uk/~johnc/teaching/fluidmechanics4/2003-04/fluids5/stress.html

Sorry about the small picture - that's how it is on the website.
 

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I would assume there's a simple trigonometric identity to apply. What makes this difficult for me is that phi is present in both the x and y directions, whilst the equation somehow describes it through the x-axis.
 

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