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The discussion focuses on determining the appropriate gearmotor torque required to close a 136 lbs door measuring 40 inches wide and 85 inches high within 60 seconds. Key calculations involve the mass moment of inertia and angular acceleration, with the door's hinge located on the right side. Participants emphasize the need for precise measurements and considerations of safety factors, friction, and gravity to accurately size the gearmotor.
PREREQUISITESMechanical engineers, robotics enthusiasts, and anyone involved in designing automated door systems or selecting gearmotors for specific applications.
Thank you very much for your help. I kept struggling with finding the torque, using a different equation. That mass moment of inertia is going to help me a lottygerdawg said:Much more info needed for any kind of intelligent answer:
- This figure is plan (top) view, correct? If not, specify it so the community can determine the direction of the gravity vector. Gravity may add force requirements. Yes this is top view
- Is the door hinged? If hinged, where is the hinge? Specify it. Yes on the right side.
- If no hinged, about what axis does the door pivot? Specify it.
- door mass ≠ lbs. You better figure that out first.
- Torque = (mass moment of inertia) x (angular acceleration)
- (mass moment of inertia) will likely be estimated from inertia primitive formulas and modified with parallel axis theorem. Look 'em both up.
- (angular accel) is estimated α ≅ Δ(angular velocity)/Δ(time to accelerate)
- Add a bunch of fudge factors for safety, friction, gravity effects, windage effects, robustness, etc., and that will give your peak torque. Size the gearmotor for that.
the axis of rotation is the end of the door on the right sidejedishrfu said:The moment of inertia won't anyone here wanting to help if we don’t know the axis of rotation for the door.