Looking for a Gearmotor; How Much Torque to Close this door?

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SUMMARY

The discussion focuses on determining the appropriate gearmotor torque required to close a 136 lbs door measuring 40 inches wide and 85 inches high within 60 seconds. Key calculations involve the mass moment of inertia and angular acceleration, with the door's hinge located on the right side. Participants emphasize the need for precise measurements and considerations of safety factors, friction, and gravity to accurately size the gearmotor.

PREREQUISITES
  • Understanding of torque calculations, specifically Torque = (mass moment of inertia) x (angular acceleration)
  • Familiarity with the concept of mass moment of inertia and its estimation using inertia primitive formulas
  • Knowledge of angular acceleration and its calculation as α ≅ Δ(angular velocity)/Δ(time to accelerate)
  • Basic principles of mechanical engineering related to door mechanisms and gearmotors
NEXT STEPS
  • Research how to calculate mass moment of inertia for different shapes and configurations
  • Learn about gearmotor specifications and sizing based on torque requirements
  • Explore the effects of friction and gravity on mechanical systems
  • Investigate safety factors and design considerations in door mechanisms
USEFUL FOR

Mechanical engineers, robotics enthusiasts, and anyone involved in designing automated door systems or selecting gearmotors for specific applications.

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I'm trying to find a gearmotor that applies enough torque to close this door.

Door Mass = 136lbs
Door Dims = 40in width x 85in height
Time to close = 60sec
Door's rotation = 180 degrees

upload_2017-12-21_17-37-37.png


Any tips and advice would truly be appreciated.
 

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Do you have an actual door in mind?

Where is the door hinge axis?

If this is a real door you might simply measure the force needed to close it at the point where you plan to connect the lever arm.
 
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I can't see from the drawing how this could operate as a door closer. Is the gearmotor supposed to have a rotary output?
Is closure speed fixed? 180° open to closed in 60 seconds (2°/second) is rather slow over much of the closure range.
Take care to rescue the angel; crushing one in a door mechanism is considered poor engineering practice.
 
Much more info needed for any kind of intelligent answer:
  • This figure is plan (top) view, correct? If not, specify it so the community can determine the direction of the gravity vector. Gravity may add force requirements.
  • Is the door hinged? If hinged, where is the hinge? Specify it.
  • If no hinged, about what axis does the door pivot? Specify it.
  • door mass ≠ lbs. You better figure that out first.
  • Torque = (mass moment of inertia) x (angular acceleration)
  • (mass moment of inertia) will likely be estimated from inertia primitive formulas and modified with parallel axis theorem. Look 'em both up.
  • (angular accel) is estimated α ≅ Δ(angular velocity)/Δ(time to accelerate)
  • Add a bunch of fudge factors for safety, friction, gravity effects, windage effects, robustness, etc., and that will give your peak torque. Size the gearmotor for that.
 
tygerdawg said:
Much more info needed for any kind of intelligent answer:
  • This figure is plan (top) view, correct? If not, specify it so the community can determine the direction of the gravity vector. Gravity may add force requirements. Yes this is top view
  • Is the door hinged? If hinged, where is the hinge? Specify it. Yes on the right side.
  • If no hinged, about what axis does the door pivot? Specify it.
  • door mass ≠ lbs. You better figure that out first.
  • Torque = (mass moment of inertia) x (angular acceleration)
  • (mass moment of inertia) will likely be estimated from inertia primitive formulas and modified with parallel axis theorem. Look 'em both up.
  • (angular accel) is estimated α ≅ Δ(angular velocity)/Δ(time to accelerate)
  • Add a bunch of fudge factors for safety, friction, gravity effects, windage effects, robustness, etc., and that will give your peak torque. Size the gearmotor for that.
Thank you very much for your help. I kept struggling with finding the torque, using a different equation. That mass moment of inertia is going to help me a lot
 
The moment of inertia won't anyone here wanting to help if we don’t know the axis of rotation for the door.
 
jedishrfu said:
The moment of inertia won't anyone here wanting to help if we don’t know the axis of rotation for the door.
the axis of rotation is the end of the door on the right side
 

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