Looking for equation for change in momentum

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Homework Help Overview

The discussion revolves around finding the equation for change in momentum in the context of a baseball being pitched and then batted back. The original poster is seeking assistance due to not having access to their usual textbook.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between mass and velocity in momentum, and the importance of direction and signs in calculating change in momentum. There is an exploration of the correct identification of initial and final momentum values.

Discussion Status

Participants are actively engaging in clarifying the concepts of momentum and change in momentum. Some guidance has been provided regarding the correct approach to calculating momentum, with a focus on ensuring the correct signs and order of values are used. There is a recognition of differing interpretations of the problem.

Contextual Notes

The original poster is working with an older physics book and is facing challenges due to missing information from their usual resources. There is an emphasis on understanding the definitions and calculations related to momentum.

jjg242
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One of the questions on my test review tells me to look for the equation in the book, but i have a different book because my backpack got stolen and I can only get my hands on a old physics book at the moment. can someone help me out and let me know what equation I am looking for here? thanks,

A pitched baseball, of mass 0.2 kg, arrives at home plate with a speed of 40 m/s and is batted straight back to the pitcher with a return speed of 60 m/s. What is the magnitude of change in the ball's momentum?

a. 40 kg-m/s b. 8.0 kg-m/s c. 18 kg-m/s d. 20 kg-m/s
 
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You shouldn't need a special formula here. Do you understand that momentum is mass x velocity? The change in anything will be final value minus initial value. (Tricky part: Direction--and signs--matter.)
 
so simply:

(0.2*40)-(0.2* -60) = 20 kg-m/s

is this correct?
 
No. Your main mistake is getting the signs wrong. But you also got initial and final reversed. Fill this out:

Final momentum =

Initial momentum =

Change (Final - Initial) =
 
Doc Al said:
No. Your main mistake is getting the signs wrong. But you also got initial and final reversed. Fill this out:

Final momentum =

Initial momentum =

Change (Final - Initial) =

maybe I am finding the momentum wrong?

Final momentum = -12

Initial momentum = 8

Change (-12 - 8) = -20 since it's magnitude, just 20. I don't see how it could be anything else.
 
Exactly right! (I misread your answer before :redface:--sorry about that. You didn't make the sign error I thought you did! The only mistake was reversing initial and final, but that didn't really matter.)
 
thanks, this forum is so helpful.
 

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