A car starts at a point A at a height H above the bottom of the loop the loop. It is starting from rest and we ignore friction.
A) what is minimum value of H in terms of R such that the car moves around the loop without falling off at the top point B.
B) If R=20m and H=3.5R calculate the speed, radial and tangential acceleration
The Attempt at a Solution
A) total energy at A is equal to mgH. total energy at B is equal to mg2R + .5mv^2
Solving for H gives H=2R+v^2/2g. Minimum velocity at B is mg=(mv^2/R) V62=Rg
Substituting gives H=5/2R. Not sure if this is correct....
B) to find speed: mg(3.5R)=mgR+.5mv^2, masses cancel. v=sqrt(5gR)=sqrt(5*9.8*20)=31.3m/s
I don't know how to find tangential acceleration....
Thanks for the help