A bolt comes loose from the bottom of an elevator that is moving upward at a speed of 6.88 m/s. The bolt reaches the bottom of the elevator shaft in 3.90 s. How high up was the elevator when the bolt came loose?
d= v(initial)t + .5at^2
The Attempt at a Solution
d= 6.88(3.9) + .5(-9.89)(3.9)^2
I got the answer -48.38 but the distance is wrong... anyone see where I went wrong? Thanks