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## Homework Statement

A bolt comes loose from the bottom of an elevator that is moving upward at a speed of 6.88 m/s. The bolt reaches the bottom of the elevator shaft in 3.90 s. How high up was the elevator when the bolt came loose?

## Homework Equations

d= v(initial)t + .5at^2

## The Attempt at a Solution

d= 6.88(3.9) + .5(-9.89)(3.9)^2

I got the answer -48.38 but the distance is wrong... anyone see where I went wrong? Thanks