Lorentz Factor / Spacecraft to Star

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Homework Help Overview

The problem involves calculating the constant velocity required for a spacecraft to travel from Earth to a star located 4.2 light years away within a time frame of 3.0 years. The discussion centers around the implications of relativistic effects, particularly length contraction, and the appropriate use of units in calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the appropriate equations to use, with some suggesting the Lorentz factor and others exploring the implications of distance measured in light years versus meters. Questions arise regarding the interpretation of results and the correct application of formulas.

Discussion Status

The discussion has progressed with participants offering insights into the calculations and clarifying misunderstandings. There is acknowledgment of errors in previous calculations, and some participants express confidence in their understanding of the concepts involved.

Contextual Notes

Participants note the potential confusion arising from unit conversions and the need to maintain consistency in units throughout the calculations. The original poster expresses uncertainty about the implications of their calculated velocity.

ZedCar
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Homework Statement



A star is located 4.2 light years from Earth.

At what constant velocity must a spacecraft travel from Earth if it is to reach the star in 3.0 years time?

Homework Equations



I've been working on this for a couple of days, but I'm not entirely sure which equation to use.

Also, the fact that the distance is given in light years. Generally formulas require the distance input in metres (I'm in UK), so what would I input into a formula for distance? If I input 4.2 it may indicate 4.2 metres!

Thank you
 
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L = (gamma)-1*L0

Where L is the new length and L0 is the initial length. Solve for gamma and extract out the velocity.
 
The idea here is that when the traveler is moving, the distance to the star is length-contracted.

You can keep the distances in light years. If you include the units when you plug the various quantities in, you'll see the units cancel out, so it doesn't matter if you convert to meters first or not.
 
If I solve for v I get;

v = (L0 * c) / ( (c * t)^2 + L0^2) )^0.5

L0 = 4.2
c = 3 * 10^8
t = 3

I get an answer of v = 1.4

I'm not sure if this is correct or not? If it is correct, what is meant by 1.4? 1.4 what exactly?
 
I think you're just plugging the numbers in wrong. You have \frac{v}{c} = \frac{L_0}{\sqrt{(ct)^2+L_0^2}}Note that the denominator is larger than the numerator, so v/c must be less than 1.

Now you have t=3.0 years, so ct is the distance light travels in 3.0 years, i.e., 3.0 lightyears. So you get\frac{v}{c} = \frac{4.2}{\sqrt{3.0^2+4.2^2}} = 0.81or v=0.81c.
 
That's fantastic, thanks very much vela!

I actually see what I was doing wrong now.

In the denominator of the final eqn which you posted, I was inserting (3 x c)^2 where you have 3.0^2 and thus obtaining an answer of v = 1.4 due to the larger denominator.

Thanks again for your help! :smile:
 
Thanks for posting this thread, Zed. And thanks for the answer, vela. I was just about to review Intro Relativistic Mechanics, and this helped confirm that I'm doing it right. :D
 

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