MHB Luc's question at Yahoo Answers regarding an indefinite integral

Click For Summary
The discussion centers on finding the indefinite integral of the function x^4(5x^5+1)^7 dx. The solution involves using u-substitution, where u is defined as 5x^5 + 1, leading to the integral being rewritten as (1/25)∫u^7 du. This results in the final answer of (1/200)(5x^5 + 1)^8 + C after back-substituting for u. The response encourages further calculus problem submissions on the Math Help Boards forum. The discussion effectively addresses the integral calculation and invites community engagement.
MarkFL
Gold Member
MHB
Messages
13,284
Reaction score
12
Here is the question:

Find the indefinite integral?

x^4(5x^5+1)^7 dx

Here is a link to the question:

Find the indefinite integral? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
Mathematics news on Phys.org
Re: Luc's question at Yahoo! Answers regarding an indedinte integral

Hello Luc,

We are asked to evaluate:

$$\int x^4\left(5x^5+1 \right)^7\,dx$$

It we use the $u$-substitution:

$$u=5x^5+1\,\therefore\,du=25x^4\,dx$$

we may rewrite the integral as:

$$\frac{1}{25}\int u^7\,du=\frac{1}{25}\left(\frac{u^8}{8} \right)+C=\frac{1}{200}u^8+C$$

Now, back-substituting for $u$, we may state:

$$\int x^4\left(5x^5+1 \right)^7\,dx=\frac{1}{200}\left(5x^5+1 \right)^8+C$$

To Luc and any other guests viewing this topic, I invite and encourage you to post other calculus problems in our http://www.mathhelpboards.com/f10/ forum.

Best Regards,

Mark.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
1K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
8K
Replies
1
Views
4K