M-<M> for M operator: why not a mismatch?

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nomadreid
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In "Quantum Computation and Quantum Information" by Nielsen & Chuang, on pp. 88-89, applying basic statistical definitions to operators, one of the intermediary steps uses the expression
M-<M>
where M is a Hermitian operator, and <M> is the expected value = <ψ|M|ψ> for a given vector ψ (that is, when one is testing for |ψ>.)
What I do not understand is how one can subtract a vector from an operator. That is, <ψ|M|ψ> is a vector, and M is an operator. For example, if one took an example of M as a 2x2 matrix and ψ as a 1x2 vector, then <ψ|M|ψ> is a 1x2 vector, and then M-<M> has a mismatch in dimensions.
What am I wrongly interpreting? Thanks.
 

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Usually, if ##A## is an operator and ##\lambda## is a number, we write ##A-\lambda##. This is of course nonsense, like you indicated. But what we mean by this is actually ##A-\lambda I##, where ##I## is the identity operator. So numbers should often be seen as multiplied with some identity operator that we don't write.
 
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nomadreid
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Thanks, micromass. That clears it up completely.
 

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