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The symbol "m0" means stationary mass, but what does "m0 → 0" mean in physics?

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The symbol "m0" means stationary mass, but what does "m0 → 0" mean in physics?

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Nugatory

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@ Nugatory:

I encountered such a question in another site last month. But now piggy is here and reluctant to link those context. Ah, can we go on with the topic in a way as below?

In math we can consider that “m0” is just a mathematical symbol. We can carry out such mathematical operations as “m0 → ∞ ” or “m0 → 0”.

But in physics, for a certain particle, (if no other miscellaneous factors meddle in), m0 is an invariable.

I encountered such a question in another site last month. But now piggy is here and reluctant to link those context. Ah, can we go on with the topic in a way as below?

In math we can consider that “m0” is just a mathematical symbol. We can carry out such mathematical operations as “m0 → ∞ ” or “m0 → 0”.

But in physics, for a certain particle, (if no other miscellaneous factors meddle in), m0 is an invariable.

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Vanadium 50

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If you refuse to tell us what this is all about, how do you expect us to help you?

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Nugatory

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It is true that ##m_0## is often used to represent the rest mass of something, especially in the context of special relativity, but that's not the only way it’s used. And even in that specific context, the notation ##m_0\rightarrow 0## might be part of a discussion of how a particular physical system behaves if we replace one part of with something less massive.... or it might be something completely different.But in physics, for a certain particle, (if no other miscellaneous factors meddle in), m0 is an invariable.

So there is no answer to your question unless and until you supply that context.

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Your "case" has neither an m0, nor a zero, nor a discernible point.

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Mark44

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With that being the case, the thread is now closed.Your "case" has neither an m0, nor a zero, nor a discernible point.