A machine gun held by a soldier fires bullets at the rate of three per second. Each bullet has a mass of 30 g and a speed of 1200 m/s. Find the average force exerted on the soldier.
FΔt = mgf-mgi
The Attempt at a Solution
I attempted to do this by plugging it into the above equation 1200(.03)/ 3 = 12 to find the average force. The actual answer is 108. I know that the 3 should actually be multiplied to find the force but I am not sure why. Wouldn't that be finding the average momentum per second?