Macroscopic containers and nanometer hole (Nanoscale systems)

AI Thread Summary
The discussion revolves around the translocation of a polymer chain through a nanometer-sized hole between two macroscopic containers. The entropy of the segments in each container is calculated using polymer statistics, leading to the total entropy expression. The entropic free energy is derived as a function of the number of translocated segments, with maxima and minima identified based on segment distribution. The relationship between the translocation time and the polymer length is explored, suggesting that for large polymers, the translocation time scales linearly with the number of monomers. The participants express uncertainty about the calculations and seek clarification on the approach to solving the problems.
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Homework Statement


Consider two macroscopic containers separated by an insulating wall, which however has a circular hole of a few nanometers radius and negligible thickness. The containers (1 and 2) enclose aqueous solutions of a polymeric chain molecules (e.g. a DNA or protein). These often have strong interactions between various locations on the chain, that allow them to maintain "coiled up" spherical shapes up to several tens of nanometers in diameter. Such molecules can be "uncoiled" in solution by adding a salt or by heating

A. Consider an uncoiled polymer of N monomers translocating through the hole. At some time during the process, let m segments (1 ≤ m ≤ N-1) be in container 1, whereas the remaining N-m segments have passed through the hole into container 2. From the theory of polymer statistics, one can show that the entropy S of a chain of X segments with one end anchored at a fixed point (in this case the hole), is given by S(X) ~ -kBln(X). Here kB is Boltzmann’s constant. Note that these entropies are relative to that of the “coiled” polymer, and are hence negative. What is the entropy of the m segments in container 1? What is the entropy of the N-m segments in container 2 ? Hence what is the total entropy of the chain, SC?

B.
Assuming that the enthalpies of interaction of the polymer with the solvent are the same on both sides, the enthalpic contribution to the free energy is a constant and can be ignored. But the entropic term depends on the number of segments m that have translocated. Hence, write down the entropic free energy G = -TSC as a function of m. At what values of m (1 ≤ m ≤ N-1) does the free energy have maximum and minimum values? What are these values Gmax and Gmin? Hence, what is the free energy barrier ΔG = Gmax - Gmin for translocation of the strand, given its total length N? Also plot the dependence of the normalized free energy G/kBT on the number of translocated segments m, for N = 100.

C.
If a ‘rate constant’ k for full translocation can be approximated as an Arrhenius expression k ~ koexp(-ΔG/kBT), then the translocation time is τ ~ 1/k. Find τ as a function of N. Show that for large N, the translocation time is proportional to N. How does this compare with the theory discussed in class ?

Homework Equations


The Attempt at a Solution


A.
Since the entropy is measured as S(X) ~ -kB•ln(X) where X is the length of the segment and S(X) represents a coiled polymer, making the result negative. This means that the entropy for an uncoiled polymer would be positive. S(m) ~ -(-kB• ln(m))= kB•ln(m) is the entropy of the m segments in container 1. For the entropy of an N-m polymer i.e. container 2, the equation is S(N-m) ~ -(-kB• ln(N-m))= kB•ln(N-m)
Total Entropy is kB•ln(N-m)+ kB•ln(m) = Sc

This seems too simple. I do not believe this can be the answer for A.

B.
I do not know how to approach this problem. This is the "logic" I have come up with so far.

From the Sc above
G=-T•( kB•ln(N-m)+ kB•ln(m))
The maximum value (closest to positive) of Free Energy is when m is when ln(m) and ln(N-m) are small, which is nearly half way through. N needs to be (m+1), so that the ln(N-m)= 1. The minimum is when m=1.


C.
I will attempt this after A and B
 
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