Magnetic Field and range of potential energy

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SUMMARY

The discussion focuses on calculating the potential energy of a circular wire with a radius of 0.02m, carrying a current of 5A, in a uniform magnetic field of 1 x 10^-4 T. The torque acting on the wire is defined by the equation torque = BIA, where A is the area of the circle. The potential energy is derived from the relationship between torque and potential energy, leading to the conclusion that the potential energy can be expressed as 2BIA, with the integral of -Td(theta) used to find the function for potential energy based on the angle theta between the magnetic field and the wire's area.

PREREQUISITES
  • Understanding of magnetic fields and forces
  • Familiarity with the concept of torque in physics
  • Knowledge of potential energy calculations in electromagnetic systems
  • Basic calculus for integrating functions
NEXT STEPS
  • Study the derivation of potential energy from torque in electromagnetic systems
  • Learn about the relationship between magnetic field strength and torque
  • Explore the implications of varying angles on potential energy in magnetic fields
  • Investigate applications of torque and potential energy in real-world electromagnetic devices
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Students studying electromagnetism, physics educators, and engineers working with electromagnetic systems will benefit from this discussion.

anonymousphys
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Homework Statement


A wire is formed into a circle having a radius of .02m and placed in a uniform magnetic field of 1*10^-4. A current of 5A passes through the wire. What is the range of potential energy the wire possesses for different orientations?


Homework Equations


torque=BIA



The Attempt at a Solution



The answer is 2BIA. However, I am not sure how to relate torque to potential energy in this scenario.
 
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torque is actually equal to BIAsin(theta), where theta is the angle between the field and the area. Potential energy is just the integral of -Td(theta), so find the function for potential energy and go from there.
 

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