Magnetic Field and vectors from Two Wires

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SUMMARY

The discussion focuses on calculating the magnetic field generated by two wires with antiparallel currents using the right-hand rule and the Biot-Savart Law. The magnetic field direction at point K due to wire 1 is determined to be counter-clockwise, represented by vector #8. For the net magnetic field at point K from both wires, the correct vector is vector #3, as the magnetic fields from both wires interact. Additionally, the magnitude of the magnetic field at point L is calculated using the Biot-Savart Law, with the final expression being (\sqrt{2}\mu I)/(3\pi d).

PREREQUISITES
  • Understanding of the Right Hand Rule for magnetic fields
  • Familiarity with the Biot-Savart Law
  • Knowledge of vector addition in physics
  • Basic trigonometry for resolving components
NEXT STEPS
  • Study the application of the Biot-Savart Law in different configurations of current-carrying wires
  • Learn about vector addition techniques in electromagnetism
  • Explore the implications of magnetic field direction in various geometries
  • Investigate the effects of varying current magnitudes on magnetic field strength
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding magnetic fields generated by current-carrying conductors.

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Homework Statement


In this problem, you will be asked to calculate the magnetic field due to a set of two wires with antiparallel currents as shown in the diagram . Each of the wires carries a current of magnitude . The current in wire 1 is directed out of the page and that in wire 2 is directed into the page. The distance between the wires is 2d. The x-axis is perpendicular to the line connecting the wires and is equidistant from the wires.

As you answer the questions posed here, try to look for a pattern in your answers.



Which of the vectors best represents the direction of the magnetic field created at point K (see the diagram in the problem introduction) by wire 1 alone?
Enter the number of the vector with the appropriate direction.

189576A.jpg
189576B.jpg


Homework Equations



Right Hand Rule for a Straight Wire

The Attempt at a Solution



Using the right hand rule for a straight wire, I found out that the direction of the magnetic field is counter - clockwise. But I'm not sure which vector represents that.

Any suggestions?
 
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cse63146 said:

The Attempt at a Solution



Using the right hand rule for a straight wire, I found out that the direction of the magnetic field is counter - clockwise. But I'm not sure which vector represents that.

Any suggestions?

The magnetic field is a vector quantity and has a single direction at a given point. If you draw a magnetic line of force through K, due to the field of wire 1 alone, in which direction does the tangent to the line of force at K point?
 
The magnetic field surrounding a current-carrying wire is tangent to a circle centered on that wire. Use the right-hand rule to find which way it points. For the current coming out of the page, point your thumb in the direction of current (out) and your fingers curl in the direction of the field (counter clockwise).
 
Vector #8 best describes the direction of the magnetic field.

There's another question that asks: Which of these vectors best represents the direction of the net magnetic field created at point K by both wires?

Since I_2 = I_1, the magnetic field due to wire #2 be clock wise and the current due to wire #1 be counter - clockwise, would the vector be #1?
 
cse63146 said:
Vector #8 best describes the direction of the magnetic field.

Let's settle this one first.

Draw a circle with the centre at wire 1 and passing through K. Now draw the tangent to the circle at K. Do you still think it's vector #8?
 
http://img267.imageshack.us/img267/7536/jhjkkb0.jpg

If I drew that diagram correctly, the answer would be vector #7.
 
Last edited by a moderator:
cse63146 said:
If I drew that diagram correctly, the answer would be vector #7.

Think about the right hand rule. The current is coming toward you. It should be #3.

Try the other questions now.
 
Thanks, got the other few questions, but I'm having trouble with this one: Point L is located a distance d\sqrt{2} from the midpoint between the two wires. Find the magnitude of the magnetic field created at point L by wire 1.

So I need to use the Biot - Savart Law:

\frac{\mu_0 I}{2 \pi d}

to find the distance, I need to use the pythogorean thereom and I get distance to be \sqrt{3 d^2} = \sqrt{3} d and I would just plug that it for the d in the Biot Savart Law to obtain the equation for the magnetic field of point L by wire 1?
 
cse63146 said:
to find the distance, I need to use the pythogorean thereom and I get distance to be \sqrt{3 d^2} = \sqrt{3} d and I would just plug that it for the d in the Biot Savart Law to obtain the equation for the magnetic field of point L by wire 1?

That's it.
 
  • #10
I need to find the magnitude of the net magnetic field at point L in the figure due to both wires and I am having some trouble. I understand that the y components of the magnetic fields from the wires will cancel and just the x components will be left. Therefore, I found the magnitudes of the B_1 field and the B_2 field (magnetic fields due to wires 1 and 2) and used trig to find only the x-components and added these. However, my answer is off by a some factor and I cannot figure out why.

Using t as the angle K-1-L and K-2-L, I got:
B_1x = B_1(sin(t)) = ((\mu * I)/(2 \pi d \sqrt{}3) *(\sqrt{}2 d)/\sqrt{}3d)
B_2x = B_1x

I multiplied B_1x by 2 to get my final answer of:
(\sqrt{}2\muI)/(3\pid)

* note: mu in equations is supposed to be mu sub not and it strangely appears as if 2 and 3 are raised to the pi, they are multiplied

I believe I must have simply made a math error. Any insights would be greatly appreciated! Thank You!
 

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