Hall voltage across a 150 μm copper tape in a 0.65 T field with 23 A current

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Puting a 150 micro.m tick coper tape into a magnetic fild of 0.65. The current going through the tape = 23 A. What is the voltage on the edges of that tape ?

Homework Equations


I used this equation: U = dBS/dt
and then - > (B*r^2*pi*I)/e_0

The Attempt at a Solution


Resoult should be 7.4 microV
 
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Discussion

Just showing what the result should be is not enough; please show us what attempts you have made to obtain that result. We can't help you if we can't see what you have tried.
 
PeterDonis said:
Just showing what the result should be is not enough; please show us what attempts you have made to obtain that result. We can't help you if we can't see what you have tried.
What do you mean ? The resoult is not mine is from the book. Its what it should be not what i get. From the equation i put up i get totally difrent stuff i don't even think its the right one. I hope someone can resolve this...
 
PeterDonis said:
Just showing what the result should be is not enough; please show us what attempts you have made to obtain that result. We can't help you if we can't see what you have tried.
Sorry * hmm i didn t even see it said the attempt :P. Its the actual resoult as i said.
 
PeterDonis said:
So what do you get and how do you get it?
I use the equation that i wrote. The resoult is really irelevant cus it must be wrong but here it is.

B= 0.65 r = 0.75 * 10^-6 and I = 23 so -> (0.65 * (0.75*10^-6)^2 * pi * 23) / (1.6 * 10^-19) = 1.65 * 10^8 is what i get
 
Where did your Relevant equations come from, and what is their area of application? The information in your problem statement doesn't seem to pertain to the variables in those equations.

Hint: Look up "The Hall Effect".