Magnetic Field Calculation for Current-Carrying Wire

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SUMMARY

The discussion centers on calculating the magnetic field (B) generated by an infinitely long wire carrying a current (i) using the equation B(D) = (μ0 i) / (2πD). The permeability of free space (μ0) is defined as 4π x 10-7 T m A-1. For a current of 1.0 A at a distance of 10 cm (0.1 m), the calculation confirms that the problem is straightforward and the direction of the magnetic field must also be considered.

PREREQUISITES
  • Understanding of magnetic fields and their properties
  • Familiarity with the Biot-Savart Law
  • Knowledge of the permeability of free space (μ0)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the Biot-Savart Law for calculating magnetic fields from current-carrying conductors
  • Learn about the right-hand rule for determining the direction of magnetic fields
  • Explore applications of magnetic fields in electromagnetism
  • Investigate the effects of varying current and distance on magnetic field strength
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Students in physics, electrical engineers, and anyone interested in understanding the principles of electromagnetism and magnetic field calculations.

creativepinky
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Homework Statement



This is a two part question I just want to check I'm on the right track - it just seems too easy to be worth the marks they're given so apologies now if I'm stating the obvious:

a) Write down an equation for the magnitude B of the magnetic field at a distance D away in a vacuum from an infinitely long wire carrying a current i.

b) Find the magnitude and direction of the magnetic field at the point O located at a distance D=10cm form a wire carrying a current i = 1.0A directed into the page.


The Attempt at a Solution



For a) I've got B(D)= (μ_0 i)/2πD

Where μ_0 is the permeability of free space constant at 4π x 10^-7 T m A-1

for b) I've just put the figures into the above equation, giving:

B(D) = (4 x 3.14 x 10^-7) x 1A / (2 x 3.14) x 0.1m

That just seems far too easy - what am I missing? Many thanks
 
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You are missing that this is indeed an easy problem. :wink:

I hope you got the direction right in the second part.
 

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