Magnetic Field due to a current

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SUMMARY

The discussion focuses on calculating the magnetic field at the center of a regular n-sided polygon formed by a wire carrying current i. The magnetic field is derived using the formula B=(μ)i (cosθ-cosθ)/(4πd), resulting in B = {(μ)i (n²) sin(π/n)tan(π/n)}/2(π²)r. To deduce the magnetic field for a circular current as n approaches infinity, the limit must be taken, leading to the expression B = (μ)i/2a, where a is the radius of the circle. The participants successfully clarified the deduction process by emphasizing the importance of limits.

PREREQUISITES
  • Understanding of magnetic fields and current-carrying conductors
  • Familiarity with the Biot-Savart Law
  • Knowledge of limits in calculus
  • Basic geometry of polygons and circles
NEXT STEPS
  • Study the Biot-Savart Law for magnetic field calculations
  • Learn about limits and their applications in calculus
  • Explore magnetic fields in different geometrical configurations
  • Investigate the relationship between current and magnetic fields in circular loops
USEFUL FOR

Students and educators in physics, electrical engineers, and anyone interested in electromagnetism and the behavior of magnetic fields due to current-carrying conductors.

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INTRODUCTION: I had been doing some problems on "Magnetic field due to a current." Now i have one in which one has to find the field at the centre of a regular n-sided polygon. I don't know why I'm not getting it.
THE EXACT PROBLEM: "A regular polygon of n sides is formed by bending a wire of total length 2Πr which carries a current i.(a)Find the magnetic field at the centre of the polygon.(b)By letting n -> infinity, deduce the expression for the magnetic field at the centre of a circular current."
WHAT MY BRAIN SUGGESTED: The first part is allright.The length of each side is (2Πr)/n. Now using B=(mew)i (cosθ-cosθ)/(4Πd), i got the magnetic field at the centre of the polygon as {(mew)i (n^2) sin(Π/n)tan(Π/n)}/2(Π^2)r. But i have no idea how to get part (b).
WHAT I ALSO KNOW:The magnetic field at the centre of a circular current is (mew)i/2a, where a is the radius of the circle. How do we deduce this from the earlier expression?
CONCLUSION:I really don't know how to deduce part (b).Please help. Thanks a lot.
 
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app said:
INTRODUCTION: I had been doing some problems on "Magnetic field due to a current." Now i have one in which one has to find the field at the centre of a regular n-sided polygon. I don't know why I'm not getting it.
THE EXACT PROBLEM: "A regular polygon of n sides is formed by bending a wire of total length 2Πr which carries a current i.(a)Find the magnetic field at the centre of the polygon.(b)By letting n -> infinity, deduce the expression for the magnetic field at the centre of a circular current."
WHAT MY BRAIN SUGGESTED: The first part is allright.The length of each side is (2Πr)/n. Now using B=(mew)i (cosθ-cosθ)/(4Πd), i got the magnetic field at the centre of the polygon as {(mew)i (n^2) sin(Π/n)tan(Π/n)}/2(Π^2)r. But i have no idea how to get part (b).
WHAT I ALSO KNOW:The magnetic field at the centre of a circular current is (mew)i/2a, where a is the radius of the circle. How do we deduce this from the earlier expression?
CONCLUSION:I really don't know how to deduce part (b).Please help. Thanks a lot.
For a) express the two angles as a function of the number of sides, n.

Then take the limit as [itex]n\rightarrow\infty[/itex]

AM
 
Last edited:
Thanks...

THANKS: Thanks a lot, i got it now.I didn't remember to take the limits.:smile: :smile: :smile:
 

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