Magnetic field inside capacitor - is this right?

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SUMMARY

The discussion focuses on calculating the magnetic field inside a parallel plate capacitor with a diameter of 10 cm and a spacing of 1 mm, where the electric field is increasing at a rate of 1.0 x 10^6 V/ms. The displacement current is calculated using the formula involving the permittivity constant (8.85 x 10^-12 F/m) and the area of the capacitor plates, resulting in a value of 6.95 x 10^-8 A. The magnetic field strength is derived using the Ampere-Maxwell equation, yielding a magnetic field of 3.688 x 10^-7 T at a distance of 3 cm from the axis.

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Homework Statement


A 10 cm diameter parallel plate capacitor has a 1 mm spacing. The electric field between the plates is increasing at the rate of 1.0 * 10 ^6 V/ms. What is the magnetic field strength (a) on the axis (b) 3.0 cm from the axis


Homework Equations





The Attempt at a Solution


dE/dt = 1.0 e6
displacement current = dFlux/dt * permittivity constant = dE/dt * A * 8.85e-12
displacement current = 1.0e6 * pi * .05^2 * 8.85e-12 = 6.95e-8

The first part of the Ampere Maxwell equation falls out, leaving
B*s = displacement current

For on axis s= 0 , so is the magnetic field infinite?

3cm:
B*2pi*.03 = 6.95e-8 B = 3.688 e-7 T

Is this correct?
 
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actually I messed the problem up here. I got it now.
 
Last edited:

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