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Magnetic Field at a point between two capacitors

  1. Apr 13, 2013 #1
    1. The problem statement, all variables and given/known data

    A parallel plate capacitor has circular plates of radius 12.0 cm that are separated by a distance of 4.0 mm. The potential across the capacitor is increased at a constant rate of 1300 V/s. Determine the magnitude of the magnetic field between the plates at a distance r = 3.0 cm from the center.

    2. Relevant equations

    id = ε0A(dE/dt)

    B = [μ0id/(2∏R2)]r

    3. The attempt at a solution

    id = ε0A(dE/dt)

    dE/dt = 1300 V/s
    A = ∏R2
    R = 0.12 m
    ε0 = 8.85E-12

    id = 5.2E-10


    B = [μ0id/(2∏R2)]r

    r = 0.03 m
    R = 0.12 m
    id = 5.2E-10
    μ0 = 1.26E-6

    B = 2.17E-16

    Correct answer is 3.39E-15

    How do I get there?
     
  2. jcsd
  3. Apr 13, 2013 #2

    TSny

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    Gold Member

    Note that on the left you have the rate of change of E, but on the right you have the value of the rate of change of V.

    [I get an answer that differs from the stated correct answer by a factor of 16.]
     
  4. Apr 14, 2013 #3
    I thought E stood for Vemf. Does it stands for Electric field?
     
  5. Apr 14, 2013 #4

    TSny

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    Homework Helper
    Gold Member

    E is electric field.
     
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