Magnetic Field Of Two Parallel Wires

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Homework Help Overview

The discussion revolves around determining the points on the x-axis where the magnetic field is zero due to two parallel wires carrying currents. The first wire carries a 5.0A current and is positioned at x=-2.0 cm, while the second wire carries a 3.0A current at x=2.0 cm. The problem explores two scenarios: when the currents are in the same direction and when they are in opposite directions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Ampere's Law and the Right Hand Rule to determine the direction of the magnetic fields produced by each wire. There is uncertainty about how to set up the equations correctly and whether to solve for distance or use the distances from each wire to the point where the magnetic field is zero.

Discussion Status

Participants are actively engaging with the problem, sharing their thoughts and sketches. Some have attempted calculations but express confusion about the setup and the assumptions regarding distances. Guidance has been offered to avoid guessing and to focus on understanding the 3-D nature of the magnetic fields.

Contextual Notes

There is a mention of a specific answer expected for the case when the currents are in parallel, which adds pressure to find the correct approach. Participants are also grappling with the implications of different distances from each wire to the zero point.

rstlr
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A long wire carrying a 5.0A current perpendicular to the xy-plane intersects the x-axis at x=-2.0 cm. A second, parallel wire carrying a 3.0A current intersects the x-axis at x=2.0 cm. At what point or points on the x-axis is the magnetic field zero, (a) if the currents are in the same direction (b) if the currents are in opposite directions.


B = (u * I)/(2Pi * d)?

Im not really sure how to do this :(
 
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rstlr said:
A long wire carrying a 5.0A current perpendicular to the xy-plane intersects the x-axis at x=-2.0 cm. A second, parallel wire carrying a 3.0A current intersects the x-axis at x=2.0 cm. At what point or points on the x-axis is the magnetic field zero, (a) if the currents are in the same direction (b) if the currents are in opposite directions.


B = (u * I)/(2Pi * d)?

Im not really sure how to do this :(

Welcome to the PF.

Start with Ampere's Law, and use the Right Hand Rule to figure out the directions of the two B-fields from the t wires at poins along the x axis... Please show us your work...
 
Thanks!

Ok... so basically I have to guess at numbers till I find it?... that doesn't seem like a fun time :/
 
rstlr said:
Thanks!

Ok... so basically I have to guess at numbers till I find it?... that doesn't seem like a fun time :/

Nope. No guessing involved. You sort of wrote out Ampere's Law in your original post (OP). The only thing missing is the Right Hand Rule (which is kind of hard to write on 2-D paper). You should be able to draw a sketch of the B-field for each wire (how does the B-field circulate around each wire?), and think some about how the two B-fields add. Can you post a scan of the drawing for the homework problem? Or else at least your sketch.

Don't guess, learn how to think about these problems in 3-D. That's an important skill in this course that you're taking now, and in many of your future courses.
 
Ok... Well based on what I had drawn out earlier, if the currents were in the same direction, it would be 0 = B1 - B2 in the center. Where B1 is the 5A current and B2 is the 3A current.

Then I assume I would solve for distance (d) so it would look something like

0 = (4pi x 10^-7)(5A)/(2pi)(d) - (4pi x 10^-7)(3A)/(2pi)(d)

Since they have common denominators I would just multiply each side by d? getting

d = (4pi x 10^-7)(5A)/(2pi) - (4pi x 10^-7)(3A)/(2pi)
d = 4x10^-7 m

which obviously isn't right, so I must be doing something seriously wrong. (the answer for when they are in parallel is supposed to be .5 cm)
 
rstlr said:
Ok... Well based on what I had drawn out earlier, if the currents were in the same direction, it would be 0 = B1 - B2 in the center. Where B1 is the 5A current and B2 is the 3A current.

Then I assume I would solve for distance (d) so it would look something like

0 = (4pi x 10^-7)(5A)/(2pi)(d) - (4pi x 10^-7)(3A)/(2pi)(d)

Since they have common denominators I would just multiply each side by d? getting

d = (4pi x 10^-7)(5A)/(2pi) - (4pi x 10^-7)(3A)/(2pi)
d = 4x10^-7 m

which obviously isn't right, so I must be doing something seriously wrong. (the answer for when they are in parallel is supposed to be .5 cm)

They don't have common denominators. The two distances to the 0 point from each wire will be different if the currents are different... Otherwise you are on the right track.
 
are we solving for d? OR do you use the distances from each individual wire to point 0 as d?
 

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