Magnetic Field, Potential, Velocity

  • Thread starter fredrick08
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Homework Statement


An electron travels with speed 1.0 x 107
m/s between the two parallel charged
plates shown in the adjacent figure. The
plates are separated by 1.0 cm and are
charged by a 200 V battery. What magnetic
field strength and direction will allow the
electron to pass between the plates without
being deflected?


Homework Equations


B=([tex]\mu[/tex]/4[tex]\pi[/tex])(qvsin[tex]\theta[/tex]/r[tex]^{2}[/tex])

The Attempt at a Solution


well im pretty sure that F=0N, and the the direction the field has to be in the same direction of the velocity, so sin(theta)=0...... but i have no idea how find the field strength, anyone have any ideas???
 

Answers and Replies

  • #2
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wat can i do with this Voltage... i need a current dont i?... i cant find the right formulas, and getting really frustrated.. argh
 
  • #3
Defennder
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The question referred to a picture. It may require a picture or at least an accurate description before we can help. Is the electron travelling in a direction parallel to the plates?
 
  • #4
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yes sorry... the electron is traveling parallel through the parallel plates.. i see if i can upload pic
 
  • #5
Defennder
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Well if that's the case, no picture is required. Just think in terms of how much force is needed to counter-balance the force exerted on the particle by the E-field. Then use the Lorentz force equation to find the magnetic flux density needed.
 
  • #6
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oh i dont know if we are meant to do it like that, because we havnt done flux or lorentz....
 
  • #7
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velocity.jpg
 
  • #8
Defennder
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Well, "magnetic flux density" is another word for "magnetic field strength" and "Lorentz force" is a more general term for "force on charged particle due to B-field".
 
  • #9
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oh ok so F=(E+v X B)..... i dont understand because doesnt f have to equal 0, for the electron to pass through undisturbed, as soon as there is a force the electron is going to change direction??? unless its opposing the velocity, which would make it slow down????
 
  • #10
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thus E=V/s=200/.01=2000N/C but how do i find B?
 
  • #11
Defennder
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oh ok so F=(E+v X B)..... i dont understand because doesnt f have to equal 0, for the electron to pass through undisturbed, as soon as there is a force the electron is going to change direction??? unless its opposing the velocity, which would make it slow down????
You're missing out q here. F has to be zero in order for the electron to pass undeflected. Note that the force exerted by the E-field and that by the B-field is perpendicular to its velocity, and hence does not affect its speed in that direction.

thus E=V/s=200/.01=2000N/C but how do i find B?
Use the equation you stated earlier. Although another similar approach would be to separate the two equations: F=qE and F=Bqv and this two are acting in opposite directions, so you equate them and solve for B. Note that you have to indicate the direction in which the B-field is applied.
 
  • #12
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yes sorry i missed q... so qE=Bqv =>E=Bv=>B=E/v=2000/1x10^7=2x10^-4T in the direction of the velocity?
 
  • #13
Defennder
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Check your value for E-field. And note note that magnetic force will always act in a direction perpendicular to both the velocity and direction of the B field. Use the right-hand rule to get the direction.
 
  • #14
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ya its 20000 not 2000.... oh ok yes i remember now.... duh... lol so the direction of B will be out of the page? since the E travels + to -....
 
  • #15
Defennder
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Remember this is an electron, not a positive charged particle.
 
  • #16
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na im confused... what does this mean... wont the electron want to move towards the positive charged plate??
 
  • #17
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oh for an electron its the exact opposite, so use left hand, so its going into the page? but is my maths correct, does 2mT sound right?
 
  • #18
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no wait before i was using my left hand ad it was saying out.... my right says in, thereofre it must be out of the page???? plz help im really confused
 
  • #19
Defennder
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No I meant to say that when you apply the F=qv X B vector equation you must note that the resulting direction using the right-hand rule holds for a positive charge. The negative charge goes in the opposite direction.
 
  • #20
Defennder
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Don't use your left hand. Your right hand would do, just reverse the direction.
 
  • #21
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yes so if my right hand says the direction is into the page for a +ve charge it is out the page for a -ve charge ie, an electron?
 
  • #22
Defennder
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EDIT: Ok, you're right on this. You can visualise the +ve charged particle as moving from the right to the left. By the way, don't switch it around twice; either consider an equivalent positive charged particle or just reverse the direction at the end of your hand-twisting. Don't do both.

Just consider a positive charge from left to right (same as the electron). Assume the B-field passes into the page. Use the right hand rule and reverse the direction at the end. Is the result the direction you want? If not, assume instead the B-field passes out of the page and do the same.
 
Last edited:

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