Magnetic field produced by a current

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SUMMARY

The discussion centers on calculating the magnetic flux density produced by a single-loop coil with a current of 5 amps, using the formula β = μ0*I*n/2πr. The participants highlight discrepancies between theoretical calculations and experimental results, specifically noting a measured voltage of 6.2 mV at a distance of 10 mm from the coil. Key issues identified include the importance of using correct units and the impact of environmental factors on measurements, as well as the need for precise calculations involving the permeability of free space, μ0 = 4π × 10-7 N/A2.

PREREQUISITES
  • Understanding of magnetic flux density and its calculation.
  • Familiarity with the formula β = μ0*I*n/2πr.
  • Knowledge of the permeability of free space (μ0).
  • Basic principles of electromagnetism and experimental measurement techniques.
NEXT STEPS
  • Review the derivation and application of the formula for magnetic flux density in single-loop coils.
  • Learn about the effects of environmental factors on electromagnetic measurements.
  • Study the significance of unit conversions in physics calculations.
  • Explore advanced topics in electromagnetism, such as the Biot-Savart Law.
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators and researchers involved in experimental physics and electrical engineering.

carl binney
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Homework Statement


IMG_1081.JPG
this is the equation for flux density we have been given, the radius 30mm, z= goes in stages of 10mm, from zero to 50mm, then from zero to -50mm. that symbol at the begin of equation is 4 pie ! and the current is 5 amps. its is for a single-loop coil

Homework Equations

The Attempt at a Solution


I have tried the equation and the answer is nothing like my experimental results. which is 6.2 mV, at 10mm.
IMG_1082.JPG
 

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One of the basic formulas I've learned is that that magnet flux density can be expressed as:
β = μ0*I*n/2πr
Where μ0 is the permeability vacu vacuum, n as the numbers of the turn of the coil and r is the distance to the coil :)
 
thanks, but i missed something out the question, the equation is for single-loop coil
 
Yep, that's the equation for singlz loops,
Eitherway you've got 0.003 voltage difference and unfortunately these things happens due to many errors, one of them is that we're not living in the vacuum, :)
 
Hello Carl, welcome to PF :smile: !

Please read the guidelines . You get better help if you present a clear and concise problem.
What is this about ?
What are the relevant equations ?

Apparently you are measuring something in terms of mV.
What does that have to do with the magnetic field B ?

Also your calculations should be typed (or better: typeset). But your picture does come through clearly. Pity you don't have ##r^2## in the numerator, and it's totally unclear to me why you have ##30^2## and not ##(10^{-3})^2## in the denominator. Also, the ##10^2## should be ##(10\times 10^{-3})^2##
 
thanks again, I might seem stupid, I have only done physics since Christmas , I can't see how there is only a 0.003 voltage difference ?
 
Oh, and ##\mu_0 = 4\pi \times 10^{-7}## N/A2, not just ##4\pi##.
 
IMG_1084.JPG
hi thanks for the advice every one, 0.01 is in the equation because the first measurement of the magnetic field was measured 10 mm away from the centre of the single loop coil, is this equation correct ?
 
I get that too. Now check that you get the right units.
 

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