Magnetic Field Strength & Direction at Points 1-3

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SUMMARY

The magnetic field strength and direction at points 1 to 3 are determined using the Biot-Savart Law. For Point 1, located 2 cm above the top wire carrying a 10 A current, the magnetic field strength is calculated as B = (μ0 * 10 A) / (2π * 0.02 m). At Point 2, positioned directly between the two wires with opposite currents, the magnetic field is zero due to the cancellation of opposing fields. For Point 3, 2 cm below the bottom wire, the magnetic field strength is equal in magnitude but opposite in direction to that at Point 1. The right-hand rule is essential for determining the direction of the magnetic fields.

PREREQUISITES
  • Understanding of the Biot-Savart Law
  • Familiarity with the right-hand rule for magnetic fields
  • Knowledge of magnetic field strength calculations
  • Basic concepts of electric current and its direction
NEXT STEPS
  • Study the Biot-Savart Law in detail
  • Learn about the right-hand rule and its applications in electromagnetism
  • Explore the effects of multiple current-carrying wires on magnetic fields
  • Investigate the concept of magnetic field lines and their representation
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding magnetic fields generated by current-carrying conductors.

cemar.
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1. What are the magnetic field strength and direction at points 1 to 3 in the figure?
Okay, sorry, once again i don't know how to get the picture up here so ill describe it!
There are 2 long wires 4 cm apart, the one on top with a current of 10 A in the positive x direction and the one on the bottom with a current of 10 A in the negative x direction.
Point 1 is 2cm above the top wire.
Point 2 in directly in between the two wires.
Point 3 is 2cm underneath the bottom wire.


Homework Equations


Okay so here I am thinking something along the lines of that B = (u0/4pi)(Is 'r-hat'/r^2)
or maybe i found this equation in my notes that could be helpful and my gut says its the better bet
B = (u0I)/(2pid)


The Attempt at a Solution


Point 1 : (u0*10A)/(2pi*0.02m)
Point 2 : since it is inbetween two wires with opposite currents, so opposite fields (?) my guess is that it is equal to 0?
Point 3 : the opposite of point 1

Im also curious as to whether we assign a negative or positive value to the current??
And also would the bottom wire have an effect on the magnetic field at point 1??
 
Physics news on Phys.org
You have to decide the direction of the field by right hand clasp rule. Accordingly the field at point 1 due to top wire is coming out of the paper at a distance 2 cm from the wire and field due to bottom wire is going into the paper at a distance 6 cm from this wire. Apply the same rule to the other points.
 

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