(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two wires, each having a weight per unit length of 10^{–4}N/m, are strung parallel, one 0.3 m above the other. If the wires carry the current of same magnitude, how great must the current in each wire be for the magnetic field due to the lower conductor to balance the weight of the upper conductor? What have to be the directions of the two currents for that to work?

2. Relevant equations

Since we are not given any length, we must work per unit of length, in this case meters.

Weight = mass X gravitational acceleration.

Since we are already given the weight, we simply must find the equivalent force to create an equilibrium.

We also know I_{1}= I_{2}

F_{1}= (μ_{0}I_{1}I_{2})/(2pi X a)

3. The attempt at a solution

Simply solve for I, since I_{1}= I_{2}, we can re-write:

10^{-4}N = (μ_{0}I^{2})/(2pi X a)

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# Homework Help: Magnetic force created by one wire over another

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