1. The problem statement, all variables and given/known data A magnet produces a 0.5 T field between its poles, directed to the east. A dust particle with charge q = -8 times 10-18 C is moving straight down at 0.6 cm/s in this field. What is the magnitude and direction of the magnetic force on the dust particle? 2. Relevant equations F= qv X b 3. The attempt at a solution Tried converting .6 cm/s into m/s and solving since the sin (90) would still be 1, but it keeps telling me I am wrong.