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Magnetic Force on a Moving Charge

  1. Sep 28, 2008 #1
    1. The problem statement, all variables and given/known data
    A magnet produces a 0.5 T field between its poles, directed to the east. A dust particle with charge q = -8 times 10-18 C is moving straight down at 0.6 cm/s in this field. What is the magnitude and direction of the magnetic force on the dust particle?

    2. Relevant equations

    F= qv X b

    3. The attempt at a solution

    Tried converting .6 cm/s into m/s and solving since the sin (90) would still be 1, but it keeps telling me I am wrong.
  2. jcsd
  3. Sep 29, 2008 #2


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    Homework Helper

    Hi, you need to be more explicit as to what you have tried which you said did not correspond to the correct answer. What is your answer? It's a vector isn't it?
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