Magnetic susceptibility and relative permeability

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Homework Help Overview

The discussion revolves around the derivation of the relationship between magnetic susceptibility (χm) and relative permeability (μr), specifically the equation χm = μr - 1. The subject area is magnetic properties in physics, focusing on magnetization and the behavior of materials in magnetic fields.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss relevant equations related to magnetic properties, including relationships involving magnetization (M), magnetic field (H), and magnetic flux density (B). There are attempts to connect these equations to derive the desired relationship. Some participants express uncertainty about how to start or connect the equations, while others suggest substituting variables and factoring.

Discussion Status

The discussion includes various attempts to manipulate equations to derive the relationship. Some participants have made progress in their reasoning, while others are still seeking guidance on how to approach the problem. There is a mix of attempts and suggestions, with no explicit consensus reached on the derivation process.

Contextual Notes

Some participants mention needing additional relevant equations and express confusion about the connections between the variables involved. There are also indications that some users may not be following the forum's guidelines for posting homework questions.

Marwa
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Homework Statement


find the derivation of
χm=μr-1
where Xm is the magnetic susceptibility and μ is the relative permeability.

Homework Equations


M=Xm.H
M is the magnetization,H is the magnetic field
μr=μ/μo
where μo is the permeability of a vacuum,


The Attempt at a Solution


I don't know how to start ,I know some equations related to magnetic properties but i cannot connect them to each other to find the derivation.
 
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Hello Marwa,

Welcome to Physics Forums! :smile:

For convenience, I've retyped in your problem.

Derive the formula,
\chi_m = \mu_r - 1

Relevant equations:
\mathrm{\textbf{M}} = \chi_m \mathrm{\textbf{H}}
\mu = \mu_r \mu_0
I'm pretty sure you will need one or two more relevant equations.
Can you find any relevant equations that relate to the magnetic field, \mathrm{\textbf{B}}?
.
.
.
 
Relevant equations:
β=μH

βo=μoH

μr=μ/μo

β = μoH+ μoM

M=Xm.H
 
Marwa said:
Relevant equations:
β=μH

βo=μoH

μr=μ/μo

β = μoH+ μoM

M=Xm.H

Okay, with these relevant equations,
\mathrm{\textbf{M}} = \chi_m \mathrm{\textbf{H}}
\mu = \mu_r \mu_0
\mathrm{\textbf{B}} = \mu \mathrm{\textbf{H}}
\mathrm{\textbf{B}} = \mu_0 \left( \mathrm{\textbf{H}} +\mathrm{\textbf{M}} \right)
you have enough to show that
\chi_m = \mu_r - 1.
What have you tried so far?
 
I have tried :

M=Xm.H
Xm=M/H
Xm=Mμ/B
as H=B/μ
and B=μo(H+M)
Xm=(M.μ)/μo(H+M)
so Xm=μr.M/(H+M)
 
Marwa said:
I have tried :

M=Xm.H
Xm=M/H
Xm=Mμ/B
as H=B/μ
and B=μo(H+M)
Xm=(M.μ)/μo(H+M)
so Xm=μr.M/(H+M)

Try substituting
M = χmH
into
B=μ0(H+M)​
Then factor the H.
 
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I got it:

B=μo(H+M)
and M=XmH
B=μo(H+XmH)
B=μoH(1+Xm)
so μH=μoH(1+Xm)
μ/μo=μr
Xm=1-μr

Thank you.
 
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Likes   Reactions: Arun
DERIVE THE RELATIONSHIP B = μ0(H + M)
 
Inusa Adamu Gurai said:
DERIVE THE RELATIONSHIP B = μ0(H + M)
I need the same,
Help me of you find it
 
  • #10
Arun said:
I need the same,
Help me of you find it
Hello @Arun,

I suggest starting a new thread if you need help on this. Be sure to use the automatic template (problem statement, relevant equations, attempted solution, and so forth).
 

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