Magnetostatics problem: find B and H

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Homework Statement



A long wire carries a current I and is centered in a long hollow cylinder of inner radius a and outer radius b. The cylinder is made of a linear material with permeability [tex]\mu[/tex]. Find [tex]\mathbf{B}[/tex] and [tex]\mathbf{H}[/tex] everywhere.

Homework Equations





The Attempt at a Solution



The only free current in the problem is the current in the wire. Therefore, by Ampere's law,

[tex]\mathbf{H} = \frac{I}{2 \pi\ p}\ \boldsymbol{\hat{\phi}}[/tex]

(I'm using cylindrical coordinates with the wire at p = 0 and the current moving in the +z direction.)

For 0 < p < a and b < p, we have [tex]\mathbf{B}=\mathbf{H}[/tex]. For a < p < b, we have [tex]\mathbf{B} = \mu\ \mathbf{H}[/tex].


If this solution is correct, would anything be changed if I said that the hollow cylinder with permeability [tex]\mu[/tex] was also a conductor (made of steel, say)?
 
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Your solutions look right to me, but you use the cgs system & I use SI so to that extent I don't know, but as I say they all look right.

The fact that it would be a conductor, e.g. Cu, is of no consequence. Cu is non-magnetic.

But - you said steel - steel has a very high permeability so to that extent your numbers would be quite different inside the steel.