Magnitude of buoyant force in fluids of different densities

  • Thread starter Thread starter I_Try_Math
  • Start date Start date
I_Try_Math
Messages
117
Reaction score
25
Homework Statement
A penguin floats first in a fluid of density ##\rho_0##, then in a fluid of density 0.95##\rho_0##, and then in a fluid of density 1.1##\rho_0##. (a) Rank the densities according to the magnitude of the buoyant force on the penguin, greatest first.
Relevant Equations
##\rho = \frac{m}{V}##
##p = \frac{F}{A}##
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?
 
Physics news on Phys.org
I can see now that my reasoning doesn't work because it assumes the volume of water displaced is constant. I'll have to think about this some more.
 
I_Try_Math said:
I can see now that my reasoning doesn't work because it assumes the volume of water displaced is constant. I'll have to think about this some more.
What did Archimedes realise about the quantity of fluid displaced by a floating object?
 
haruspex said:
What did Archimedes realise about the quantity of fluid displaced by a floating object?
That the weight of the displaced fluid will be equal to the weight of the floating object, I believe. I think I understand why the answer in the textbook is correct.
 
Remember: a floating body displaces its own weight of fluid;
A submerged body displaces its own volume of fluid.
Whether it floats or sinks depends on its own density relative to the fluid.
 
I have always assumed that Archimedes figured this out by imagining replacing the submerged portion with an equal volume of water, exactly filling the void in the water that would be created by removing the submerged portion. Clearly that water would float, so the force exerted on it by the surrounding water must be equal to its weight.
 
I_Try_Math said:
Homework Statement: A penguin floats first in a fluid of density ##\rho_0##, then in a fluid of density 0.95##\rho_0##, and then in a fluid of density 1.1##\rho_0##. (a) Rank the densities according to the magnitude of the buoyant force on the penguin, greatest first.
That's not worded correctly. It should be asking you to rank the magnitudes of the buoyant forces. Clearly, the densities are not all equal.
 
haruspex said:
I have always assumed that Archimedes figured this out by imagining replacing the submerged portion with an equal volume of water, exactly filling the void in the water that would be created by removing the submerged portion.
That's the version that appears in the textbooks. I also assume it's true.
haruspex said:
Clearly that water would float, so the force exerted on it by the surrounding water must be equal to its weight.
You mean that water would be in a state of neutral buoyancy.
 
Herman Trivilino said:
That's not worded correctly. It should be asking you to rank the magnitudes of the buoyant forces. Clearly, the densities are not all equal.
The wording is awkward but not actually wrong. It means rank the fluids according to the buoyant forces they are exerting, but since the only way the fluids have been assigned labels is by their density variable names, those are what have to be listed.
Herman Trivilino said:
That's the version that appears in the textbooks. I also assume it's true.

You mean that water would be in a state of neutral buoyancy.
Yes, necessarily.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
4K
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
4
Views
4K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K