1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Magnitude of perpindicular vectors

  1. May 24, 2012 #1
    1. The problem statement, all variables and given/known data


    v = (-4, -2) and need to find alll vectors of magnitude 4 that are perpindicular to v

    2. Relevant equations



    3. The attempt at a solution

    I tried
    let (x, y) be the vector of interest.

    -4x -2y = 0
    x^2 + y^2 = 16.

    Is this the right track? If so, how do i solve from here?
     
  2. jcsd
  3. May 24, 2012 #2

    Curious3141

    User Avatar
    Homework Helper

    Yes, right track. Just solve the simultaneous equation pair. Substitution is the easiest way. Use the first equation to get y in terms of x, then substitute into the second.

    You should now get two values of y (remember to take both positive and negative square roots). Put that back into the first equation to get the corresponding values of x. Each solution (x,y) corresponds to a valid vector meeting the conditions.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Magnitude of perpindicular vectors
  1. Vector and magnitude (Replies: 6)

  2. Vector magnitude (Replies: 1)

  3. Vector Magnitudes (Replies: 1)

  4. Vectors and magnitudes (Replies: 13)

Loading...