Magnitude of the maximum torque on a current loop.

  • Thread starter shaizen
  • Start date
  • #1
2
0

Homework Statement


A current loop in a motor has an area of 0.62 cm^2. It carries a 207 mA current in a uniform field of 1.43 T. What is the magnitude of the maximum torque on the current loop?

A = .0062 m^2
I = .207 A
B = 1.43 T


Homework Equations


F=(IA)Bsin(theta)


The Attempt at a Solution


F = (.207)(.0062)(1.43)sin90 = .001835262N*m

I am not sure what I am doing wrong. I have finished all the problems assigned to me but the computer tells me this answer is wrong. Any help would be appreciated!
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
7
Hi shaizen, welcome to PF.
Your conversion of area from cm^2 to m^2 is wrong. Check it.
 
  • #3
2
0
Thanks a lot! I knew it was something simple I wasn't paying attention to.
 

Related Threads on Magnitude of the maximum torque on a current loop.

Replies
0
Views
3K
Replies
3
Views
20K
  • Last Post
Replies
3
Views
3K
Replies
4
Views
8K
Replies
7
Views
2K
  • Last Post
Replies
0
Views
5K
  • Last Post
Replies
6
Views
7K
  • Last Post
Replies
3
Views
7K
Replies
2
Views
17K
Replies
3
Views
5K
Top