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Magnitude of the maximum torque on a current loop.

  1. Oct 12, 2009 #1
    1. The problem statement, all variables and given/known data
    A current loop in a motor has an area of 0.62 cm^2. It carries a 207 mA current in a uniform field of 1.43 T. What is the magnitude of the maximum torque on the current loop?

    A = .0062 m^2
    I = .207 A
    B = 1.43 T


    2. Relevant equations
    F=(IA)Bsin(theta)


    3. The attempt at a solution
    F = (.207)(.0062)(1.43)sin90 = .001835262N*m

    I am not sure what I am doing wrong. I have finished all the problems assigned to me but the computer tells me this answer is wrong. Any help would be appreciated!
     
  2. jcsd
  3. Oct 12, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Hi shaizen, welcome to PF.
    Your conversion of area from cm^2 to m^2 is wrong. Check it.
     
  4. Oct 12, 2009 #3
    Thanks a lot! I knew it was something simple I wasn't paying attention to.
     
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