A current loop in a motor has an area of 0.62 cm^2. It carries a 207 mA current in a uniform field of 1.43 T. What is the magnitude of the maximum torque on the current loop?
A = .0062 m^2
I = .207 A
B = 1.43 T
The Attempt at a Solution
F = (.207)(.0062)(1.43)sin90 = .001835262N*m
I am not sure what I am doing wrong. I have finished all the problems assigned to me but the computer tells me this answer is wrong. Any help would be appreciated!