Magnitude of the maximum torque on a current loop.

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SUMMARY

The maximum torque on a current loop with an area of 0.62 cm², carrying a 207 mA current in a uniform magnetic field of 1.43 T, is calculated using the formula F = (IA)Bsin(θ). The correct area conversion from cm² to m² is crucial, as the area should be 0.0062 m². The correct calculation yields a torque of 0.001835262 N·m when using sin(90°).

PREREQUISITES
  • Understanding of torque and magnetic fields
  • Familiarity with the formula F = (IA)Bsin(θ)
  • Knowledge of unit conversions, specifically from cm² to m²
  • Basic principles of electromagnetism
NEXT STEPS
  • Review unit conversion techniques for area measurements
  • Study the principles of torque in electromagnetism
  • Learn about the effects of varying angles in torque calculations
  • Explore practical applications of current loops in motors
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Students studying electromagnetism, physics educators, and anyone involved in electrical engineering or motor design.

shaizen
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Homework Statement


A current loop in a motor has an area of 0.62 cm^2. It carries a 207 mA current in a uniform field of 1.43 T. What is the magnitude of the maximum torque on the current loop?

A = .0062 m^2
I = .207 A
B = 1.43 T


Homework Equations


F=(IA)Bsin(theta)


The Attempt at a Solution


F = (.207)(.0062)(1.43)sin90 = .001835262N*m

I am not sure what I am doing wrong. I have finished all the problems assigned to me but the computer tells me this answer is wrong. Any help would be appreciated!
 
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Hi shaizen, welcome to PF.
Your conversion of area from cm^2 to m^2 is wrong. Check it.
 
Thanks a lot! I knew it was something simple I wasn't paying attention to.
 

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