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## Homework Statement

A current loop in a motor has an area of 0.62 cm^2. It carries a 207 mA current in a uniform field of 1.43 T. What is the magnitude of the maximum torque on the current loop?

A = .0062 m^2

I = .207 A

B = 1.43 T

## Homework Equations

F=(IA)Bsin(theta)

## The Attempt at a Solution

F = (.207)(.0062)(1.43)sin90 = .001835262N*m

I am not sure what I am doing wrong. I have finished all the problems assigned to me but the computer tells me this answer is wrong. Any help would be appreciated!