1. The problem statement, all variables and given/known data The current loop of the radius b as shown in figure is mounted rigidly on the axle,midway between the two supporting cords.In the absence of the external magnetic field,the tension in the two cords are equal and are T.What will be the tension when a vertical magnetic field B is present?? 2. Relevant equations Torque on a current carrying loop= (cross product of dipole moment vector and magnetic field vector) Magnetic moment of loop=I × A, I is current in the loop,A is it's area And of course, Torque at a point=r×F 3. The attempt at a solution I found out the dipole moment of the whole disc by integration,through the following method. Now,as I stated in the first line of section 2,I found out the torque on the disc as well as it's direction, which came out to be,say in +x direction.Then,the torque due to the left string (T1) and the right string (T2) are coming out to be in -x and +x directions respectively.Now,since the disc is in rotational equilibrium,all the torques along the x direction should cancel out. Which means, (Torque due to B)+ (Torque due to T2)=(Torque due to T1) Last line of section 2 is the formula used for finding direction of torques.. Also,the torque without any field is T,therefore,we get two equations,which can be sloved to obtain T1 and T2. HOWEVER,the answer given varies SLIGHTLY from what I have got. Where am I going wrong??I doubt it's the integration part.. One thing it MAY be is...the disc is NOT IN ROTATIONAL EQUILIBRIUM,dunno...maybe Help appreciated..