Man in Elevator: What is the Force Exerted on the Elevator Floor?

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Homework Help Overview

The problem involves a 65-kg man standing in an elevator, with various scenarios presented regarding the forces he exerts on the elevator floor under different conditions of motion, including stationary, accelerating upward, and moving at constant velocity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the forces exerted by the man under different elevator conditions, questioning how to approach scenarios involving constant velocity and acceleration without time data. Some participants suggest looking into Newton's first law to clarify the relationship between acceleration and constant speed.

Discussion Status

The discussion includes attempts to understand the relationship between weight, acceleration, and force exerted on the elevator floor. Some participants express uncertainty about the adequacy of their work, while others indicate they have resolved their confusion with assistance.

Contextual Notes

Participants are navigating the constraints of the problem, including the lack of time data for certain scenarios and the implications of constant velocity on force calculations.

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Force Of Man On Elevator

Homework Statement



An 65- kg man stands in an elevator. What force does he exert on the floor of the elevator under the following conditions? The elevator is stationary.
Answer:637.65N

The elevator accelerates upward at 2.3 m/s2.
Answer:787.15N

The elevator rises with constant velocity of 3.1 m/s.

While going up, the elevator accelerates downward at 1.7 m/s2.
Answer:527.15N

The elevator goes down with constant velocity of 6.3 m/s.

Homework Equations


EF=0


The Attempt at a Solution



so far i have the ones where i already have the acceleration but i don'tknow how to do the ones with velocity because i don't have a t(time) i thought maybe i could do the same and multiply 3.1m/s*65kg which is 201.5 and then use the formula EF=0 so EF=0=-201.5-637.65 which equals 839.15 but this was wrong, could you just give me an idea on how to get started and help would be greatly appreciated.
 
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Do I not have enough work swown?
 
Cole07 said:
Do I not have enough work swown?
you need only to look at Newton's first law to arrive at a solution. What is the acceleration of the elevator and person when they are moving at constant speed?
 
how do i get to the acceleration when i don't have anything but weight and velocity?
 
i have figured it out thank you for your help.
 

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