Manipulating quadratic and exponential expressions

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SUMMARY

The discussion focuses on the function L(t) = 5.3 x 1.025^t, which models the literacy rate in India over time. The key question is determining which equivalent function represents the time it takes for the literacy rate to triple. The correct answer is derived from the equation 3 = 1.025^t, leading to t = log(3)/log(1.025), which approximates to 44.5 years. This confirms that option (a) L(t) = 5.3 x 3^t/44.5 is the correct equivalent function.

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I am having so much trouble figuring this out, I would really appreciate some help.

The question is:
The following function, L, gives the approximate percent literacy rate in India t years after 1900.

L(t)=5.3 x 1.025^t

Which of the following equivalent functions shows, as a constant or coefficient, the approximate number of years it took for the literacy rate to triple?

(a) L(t)=5.3 x 3^t/44.5
(b) L(t)=5.3 x 1.077^t/3
(c) L(t)=5.3 x 1.008^3t
(d) L(t)=3 x 1.025^t+23

Thanks so much. I know what the answer is, but I just have no idea why it is the answer. I just want to understand :(
 
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initial literacy percentage is $L(0) = 5.3 \cdot (1.025)^0 = 5.3$

triple literacy percentage is $3 \cdot 5.3$ ...

$3 \cdot 5.3 = 5.3 \cdot (1.025)^t$

$3 = 1.025^t$

$\log(3) = t\log(1.025) \implies t = \dfrac{\log(3)}{\log(1.025)} \approx 44.5 \text{ years}$

... now look at equation (a)
 

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