Mass and Moment of Inertia of a Planet

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SUMMARY

The discussion focuses on calculating the mass and moment of inertia of a gaseous spherical planet with a nonconstant density defined by ρ(r) = ρ₀(1 - r/R). The total mass of the planet is determined to be (ρ₀ * π * R³) / 3. The moment of inertia is correctly derived as (4/15) * M * R², where M is the total mass of the planet. The use of average density in calculating the moment of inertia is incorrect, as the moment of inertia must account for the varying density throughout the planet.

PREREQUISITES
  • Understanding of calculus, specifically integration techniques.
  • Familiarity with concepts of mass and moment of inertia.
  • Knowledge of spherical coordinates and density functions.
  • Experience with physical properties of materials, particularly in astrophysics.
NEXT STEPS
  • Study the derivation of moment of inertia for nonuniform density objects.
  • Learn about integration techniques for spherical shells and disks in physics.
  • Explore the implications of varying density in astrophysical models.
  • Investigate the properties of gaseous planets and their structural mechanics.
USEFUL FOR

Students and professionals in physics, particularly those focusing on astrophysics and planetary science, as well as anyone involved in calculating physical properties of celestial bodies.

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Homework Statement


There is a gaseous spherical planet with a nonconstant density rho(r) = rho_o (1 - r / R), where rho_0 is the maximum density attained at the planet's core, R is the radius of the planet, and r is the distance from the center of the planet.
Use calculus to find the total mass of the planet in terms of rho_0 and R. Then find the moment of inertia of the planet in terms of its total mass M and R.


Homework Equations





The Attempt at a Solution



I found the Mass of the planet as (rho_o * pi *R3)/3

I integrated thin spherical shells to find the total mass using the integral - 4piR2dr*density

Then I found average density as rho_o/4

Now, I am using the integration of thin solid disks to find the moment of inertia of the sphere...which comes out to be 8/15 * density*pi R5

If we substitute the averahe density in terms of M in the above equation, the answer comes out to be 2/5 * M*R2 but I think the correct answer is 4/15*M*R2

Can anyone tell me if I am correct or am I doing something wrong
 
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You can't use the average density to find the moment of inertia. rho_0*pi*R^3/3 is the mass all right. To get the moment of inertia, I used that the moment of inertia of a hollow sphere is (2/3)*m(r)*r^2. m(r)=rho(r)*4*pi*r^2*dr. Integrating the whole thing does give (4/15)*M*R^2. It would be tough to use disks, since they don't have uniform density.
 
Thanks

I got it. I guess I was too impatient to think clearly :)
 

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