Mass defect - where does it go to?

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SUMMARY

The discussion centers on the concept of mass defect in nuclear physics, specifically in the fusion of nucleons to form deuterium. It highlights the mass discrepancy between the initial nucleons and the resulting nucleus, which is explained by the equation E = mc². The conversation clarifies that the abandonment of relativistic mass in favor of invariant mass does not alter the fundamental understanding of mass defect and energy conversion. Instead, both frameworks describe the same physical phenomenon using different terminologies.

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  • Knowledge of special relativity and invariant mass
  • Basic concepts of binding energy in atomic nuclei
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Michio Cuckoo
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In nuclear physics, when two nucleons (e.g. a proton and neutron) fuse together, they release binding energy.

There is a mass discrepancy between the newly formed deuterium nucleus and the initial mass of both nucleons.

This mass defect is related to the binding energy by the famous equation E = mc^2.

But is the loss in mass really converted to energy? I read that in a modification of special relativity, scientists have abandoned the concept of relativistic mass and opted for invariant mass instead. In this case, where does the mass defect come from?
 
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Michio Cuckoo said:
But is the loss in mass really converted to energy? I read that in a modification of special relativity, scientists have abandoned the concept of relativistic mass and opted for invariant mass instead. In this case, where does the mass defect come from?

That's not a "modification" of special relativity, it's just a different way of talking about the same phenomenon. You can either speak in terms of relativistic mass and say that E=mc[itex]^{2}[/itex], or you can speak in terms of the rest mass and say that E[itex]^{2}[/itex]=p[itex]^{2}[/itex]c[itex]^{2}[/itex]+m[itex]^{2}[/itex]c[itex]^{4}[/itex]. The latter is more generally used these days, but the former is still convenient for problems like your deuterium atom.
 

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