Mass of a Person on a Ferris Wheel - Physics Homework

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SUMMARY

The discussion focuses on calculating the mass of a person riding a Ferris wheel using scale readings at the top and bottom of the wheel. Given a radius of 16 m, the scale reads 510 N at the top and 666 N at the bottom. The forces acting on the person include gravitational force, normal reaction force, and centripetal force. The normal reaction force is greater at the bottom due to the need to provide sufficient centripetal force to maintain circular motion, while at the top, it is less than gravitational force.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of centripetal force and its calculation (mv²/R)
  • Familiarity with normal reaction force and its role in circular motion
  • Basic principles of uniform circular motion
NEXT STEPS
  • Study the relationship between normal reaction force and gravitational force in circular motion
  • Learn how to calculate centripetal acceleration and its impact on forces
  • Explore real-world applications of circular motion physics, such as roller coasters
  • Investigate the effects of varying mass on normal reaction force in different scenarios
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to forces in circular dynamics.

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Homework Statement



I have to find the mass m of a person riding a ferris wheel sitting on a bath scale.
Given data:
R=16 m
Scale reading on top of ferris wheel = 510 N
Scale reading at bottom of the ferris wheel= 666 N

Homework Equations



F=ma

For uniform circular motion we have:
a_{rad}=\frac{v^2}{R}

The Attempt at a Solution



I know that three forces are acting on the person on both top and bottom of the wheel:
gravity Fg, the normal force Fn and the centripetal acceleration.

The reason that I'm stuck is that I can't understand this:

What is the resulting force? the centripetal acceleration?
I have read that the normal force in this situation is bigger at the bottom that on the top? Why is that?

If I answer these questions I can use Newtons 2nd law.

Thanks.
 
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Fleet said:

Homework Statement



I have to find the mass m of a person riding a ferris wheel sitting on a bath scale.
Given data:
R=16 m
Scale reading on top of ferris wheel = 510 N
Scale reading at bottom of the ferris wheel= 666 N

Homework Equations



F=ma

For uniform circular motion we have:
a_{rad}=\frac{v^2}{R}

The Attempt at a Solution



I know that three forces are acting on the person on both top and bottom of the wheel:
gravity Fg, the normal force Fn and the centripetal acceleration.

The reason that I'm stuck is that I can't understand this:

What is the resulting force? the centripetal acceleration?
I have read that the normal force in this situation is bigger at the bottom that on the top? Why is that?

If I answer these questions I can use Newtons 2nd law.

Thanks.

Acceleration is not a force!

You should be referring to, and calculating, centripetal Force mv2/R

The force you are calling the Normal Force, is correctly named the Normal Reaction Force.

Being a Reaction Force it is as big as it needs to be, that is why it is bigger at the bottom of the loop than at the top.

The net force [the centripetal force] at the bottom is directed up. You have to add a large upward Reaction force to the weight force to get an answer that is directed up.
The net force [the centripetal force] at the top is directed down. You have to add a smaller upward Reaction force to the weight force to get an answer that is directed down.

and note: there are only two forces acting on the passenger. The weight force, due to gravity, and the Normal Reaction Force - due to the passenger contacting the seat.

Those two combine to give the net force in many situations - In this case it is the centripetal force.
 
Thanks for the clarifications. The normal reaction force is directed upwards at both top and bottom, right? So Fn is less than gravity on the top and bigger than gravity at the bottom?

What exactly makes the normal reaction force change magnitude?
 
Fleet said:
Thanks for the clarifications. The normal reaction force is directed upwards at both top and bottom, right? So Fn is less than gravity on the top and bigger than gravity at the bottom?

What exactly makes the normal reaction force change magnitude?

The reaction force is exactly that - a reaction.
Place you hand on a table - the table pushes back with a certain force.
Now push a little harder on the table - the table pushes back a little harder.
Now push on the table as hard as you can - the table pushes back as hard as you could.

place a 500kg mass on the table - and either the table will push back with sufficient force to support it, or the table will collapse.

Friction is a reaction force too. the uR calculation [coefficient of Friction x Reaction force] tells you the maximum possible friction force [analogous to the strength of the table above].

Suppose uR worked out to be 100N

if you push a mass on that surface with a force of 5N, friction will be 5N, and nothing moves.
Push with 20N, friction is 20N
Push with 80N, friction is 80N
Push with 100N, friction is 100N
Push with 120N and the mass moves.
 

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