The position of a mass that is oscillating on a spring is given by x(t) = (14.5cm)cos[(14.0s-1)t].
What is the speed of the mass when t = 0.820 s?
W= Angular frequency
x(t) = ACos(Wt)
v(t) = -WASin(Wt)
The Attempt at a Solution
v(0.820) = (-14.0)(14.5)Sin[(14.0)(0.820)]
= -40.4 cm/s
This seems so easy and yet apparently I have the wrong answer... any insight? :/ Thanks in advance